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3 years ago

Round 248,739 to the nearest hundred

Mathematics

1 answer:

vampirchik [111]3 years ago

7 0

Look at your hundredth spot which is where the 7 is. So…

248, 739

Since 3 is not 5 or higher you cant round 7 up to 8. So your correct answer is 248,700

Hope this helps!

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Which numbers round to 3,100 when rounded to the nearest hundred

Furkat [3]

one number that could round to 3 100 when rounded is 3 120

5 0

3 years ago

2(3x-7)=34 please help

IrinaK [193]

Answer:

x=8

Step-by-step explanation:

2*3x=6x

2*-7=-14

6x-14=34

6x+14=34+14

6x=48

6x/48

x=8

3 0

2 years ago

And this one too (1 answer is off on down.)

agasfer [191]

Answer:

(-3,4)

Step-by-step explanation:

I'm not sure of how to explain how it is but basically the point it rotated and then it ends up on the coordinate, (-3,4)

5 0

2 years ago

Read 2 more answers

Please hurry. Solve the equation

Lelu [443]

The value of x is $5\sqrt[3]{25}$ .

Solution:

Given expression is $-7=8-3 \sqrt[5]{x^{3}}$ .

Switch both sides.

$8-3 \sqrt[5]{x^{3}}=-7$

Subtract 8 from both side of the equation.

$8-3 \sqrt[5]{x^{3}}-8=-7-8$

$-3 \sqrt[5]{x^{3}}=-15$

Divide by –3 on both side of the equation.

$$\frac{-3 \sqrt[5]{x^{3}}}{-3} =\frac{-15}{-3}$

$\sqrt[5]{x^{3}}=-5$

To cancel the cube root, raise the power 5 on both sides.

$(\sqrt[5]{x^{3}})^5=(-5)^5$

$x^3=3125$

To find the value of x, take square root on both sides.

$\sqrt[3]{x^3}=\sqrt[3]{25}$

$x=5\sqrt[3]{25}$

Hence the value of x is $5\sqrt[3]{25}$ .

5 0

2 years ago

Factor -2.9 out of 8.7b – 11.6.

Mama L [17]

Step-by-step explanation:

Since 8.7b = (-2.9) * (-3b),

and -11.6 = (-2.9) * (4),

8.7b - 11.6 = -2.9(4 - 3b).

6 0

2 years ago