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Alika [10]
3 years ago
8

Round 248,739 to the nearest hundred

Mathematics
1 answer:
vampirchik [111]3 years ago
7 0

Look at your hundredth spot which is where the 7 is. So…

248, 739

Since 3 is not 5 or higher you cant round 7 up to 8. So your correct answer is 248,700

Hope this helps!

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A bus as speed of 20m/s begin to slow at constant acceleration of 8.00m/s2 along a straight line find the average speed for the
MrRissso [65]

Answer:

-20 m/s.

Step-by-step explanation:

The computation of the average speed is shown below:

Given that

The initial velocity of the bus, u = 20 m/s

Aceleration of the bus, -a = 8 m/s²

time of motion, t = 5 s

Now The final velocity of the bus is  

v = u + at

v = 20 + (-8 × 5)

v = 20 - 40

v = -20 m/s.

6 0
3 years ago
PLEASE HELP ILL GIVE BRAINLIEST
Alexeev081 [22]

Answer: A.

Step-by-step explanation:

4 0
3 years ago
Write an exponential function y = abx for a graph that includes (2, 24) and (3, 48).
labwork [276]
I think you mean y=ab^x.
First, plug in the values of x=2 and y=24 for the first equation, and x=3 and y=48 for the second one:

24 = ab^2
48 = ab^3

divide equation 2 by equation 1:
2 = b^1

or, more simply:
2 = b

now plug b into one of the equations to get "a":

24 = a*2^2
24 = a*4
6 = a

So, the answer is y = 6(2)^x
(I think you need to specify the power of x in your answers)
7 0
3 years ago
Read 2 more answers
I rlly need help with this :(
kobusy [5.1K]

Using the normal distribution, it is found that:

a) The pilot is at the 72th percentile.

b) 19.13% of pilots are unable to fly.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 72.6, \sigma = 2.7.

Item a:

The percentile is the <u>p-value of Z when X = 74.2</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{74.2 - 72.6}{2.7}

Z = 0.59

Z = 0.59 has a p-value of 0.7224.

72th percentile.

Item b:

The proportion that is able to fly is the <u>p-value of Z when X = 78 subtracted by the p-value of Z when X = 70</u>, hence:

X = 78:

Z = \frac{X - \mu}{\sigma}

Z = \frac{78 - 72.6}{2.7}

Z = 2

Z = 2 has a p-value of 0.9772.

X = 70:

Z = \frac{X - \mu}{\sigma}

Z = \frac{70 - 72.6}{2.7}

Z = -0.96

Z = -0.96 has a p-value of 0.1685.

0.9772 - 0.1685 = 0.8087 = 80.87%.

Hence the percentage that is unable to fly is:

100 - 80.87 = 19.13%.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0
2 years ago
What is the best method to solve griedent and midpoint in math<br><br>40!! point​
Aleks [24]
I usually add x and divide by too and add y and divide by 2
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3 years ago
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