Answer:
This is an exponential growth equation of the form:
f(t) = A*(r)^t
Where:
A is the initial quantity of something, suppose that is the population of some kind of animal
r is the rate of growth
t is the variable, usually represents a unit of time.
f(t) is the population of the animal at the time t.
For this question, we have the equation:
b(t) = 1200*(1.8)^t
And this represents the population of a kind of bacteria as a function of time.
a) 1200 is the initial population of the bacteria.
b) the 1.8 is the rate of growth.
c) Now we have the equation:
b(t) = 1000*(1.8)^t
In this case, 1000 will represent the initial population of bacteria for this second study.
And the difference between the 1200 for the first study, and the 1000 for this second study, means that for the first study the initial population of bacteria was larger. (200 units larger).
