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TEA [102]
3 years ago
15

Find the sum (3x - 4) + (9x - 7)

Mathematics
1 answer:
Levart [38]3 years ago
6 0

Answer:
12x - 11


Step by step
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Two consecutive odd integers have a sum of 44. Find the integers.
ivanzaharov [21]

Step-by-step explanation:

Answer

Let2odintegers

(2n+1),(2n+3)

→(2n+1)+(2n+3)=44

⇒4n+4=44

⇒4n=40

⇒n=10

then,integerare

2n+1=21

2n+3=23

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2 years ago
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Change each of the following decimals to a fraction. Reduce your answer to its lowest terms.
cluponka [151]
7/100

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2 years ago
If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)
sweet-ann [11.9K]

Answer:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

Step-by-step explanation:

Given

tan\theta = 3

Required

Find

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)

Calculate tan(\theta + \pi) \ and\ tan(\theta+2\pi)

Using tan rule

tan(\theta + \pi)  = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}

So:

tan(\theta + \pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + \pi)  = \frac{tan\theta}{1 }

tan(\theta + \pi)  = \tan\theta

tan(\theta+2\pi)

tan(\theta + 2\pi)  = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}

tan(\theta + 2\pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + 2\pi)  = \tan\theta'

'So:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = tan\theta +tan\theta +tan\theta

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

4 0
2 years ago
⚠️ILL GIVE BRANLIEST!
SSSSS [86.1K]

Answer:

c

Step-by-step explanation:

3 0
2 years ago
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