Without rounding, I make it six. You could do it this way
54527/5^6 comes to a little over 3. That should be close enough. I'm going to check this by doing the divisions. I could let the computer do it, but I'd like to see if there's a pattern. There isn't and the correct answer is
6 <<<< divisions.
Hey!
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Solution:
We can get two different ways of 1:6 by add +1:+6.
1 + 1 = 6 + 6
2:12
2 + 1 = 12 + 6
3:18
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Answer:
2:12 and 3:18
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Hope This Helped! Good Luck!
Morgan earns more money per hour on saturday bc 63/6 = 10.5 and that’s more than 9.5 so
The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
<h3>What is the approximation about?</h3>
From the question:
Mars: F(x) = 2/3
Therefore, If x = 15
Then:
f (15) = 2/3 ![\sqrt[8]{15}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B15%7D)
= 16/3
= 20.7ft/s
Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
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