Answer:
The proportion of sweet cherries that weigh less than 5 ounces is 23.88%.
Step-by-step explanation:
We are given that the weight of sweet cherries is normally distributed with mean μ = 6 ounces and standard deviation σ = 1.4 ounces.
Let X = the weight of sweet cherries
SO, X ~ Normal(μ = 6 ounces , σ = 1.4 ounces)
The z-score probability distribution for the normal distribution is given by;
Z =
~ N(0,1)
where,
= population mean = 6 ounces
= standard deviation = 1.4 ounces
Now, the proportion of sweet cherries that weigh less than 5 ounces is given by = P(X < 5 ounces)
P(X < 5 ounces) = P(
<
) = P(Z < -0.71) = 1 - P(Z
0.71)
= 1 - 0.7612 = <u>0.2388</u>
The above probability is calculated by looking at the value of x = 0.71 from the z table which has an area of 0.7612.
Answer:
the greatest number is 107 and is greater than the smallest number 104.6
--------------------------------------------------------------
Find x :
--------------------------------------------------------------
Sum of adjacent angles on a straight line is 180.
∠ABY + ∠YBC = 180
x + 25 + 2x + 50 = 180
3x + 75 = 180
3x = 105
x = 35
--------------------------------------------------------------
Check if AC is parallel to DF :
--------------------------------------------------------------
If AC is parallel to DF,
∠YBC = ∠BEF (Corresponding angles)
∠YBC = 2x + 50 = 2(35) + 50 = 120
∠BEF = 5x - 55 = 5(35) - 55 = 120
Since ∠YBC = ∠BEF, AC and DF are parallel.
---------------------------------------------------------------------------------------------
Answer: Since ∠YBC = ∠BEF, AC and DF are parallel.
---------------------------------------------------------------------------------------------
Answer:
long term goal is to take on bigger, more challenging targets so I can assess my abilities. I plan on shaping myself during this initial time so that I'm prepared to deliver on bigger targets later. Although I've been in this field for a while now, I haven't been able to utilize my entire set of skills.
Step-by-step explanation:
hope it helps a little idk how to answer that completely
Assuming that means the diameter is 6in
so then
vsphere=(4/3)pir^3
r=d/2
d=6
6/2=3=r
vcube-vsphere=space
vcube=side^3=6^3=216
vsphere=(4/3)pi3^3=36pi=113.093755
space=216-113.083755=102.9026644707 cubic inches of empty space