Answer:
Step-by-step explanation:
SIDE OF THE SQUARE = 6 cm = DIAMETER OF THE CIRCLE.
AREA OF THE CIRCLE = (Pi/4)*6^2 = [(22/7)/4]*36 = 22*9/7 = 28.2857 sqcm
or
First, find the side length of the square. (Find the square root of 36 cm^2, to get 6 cm as the side length of the square).
Second, find the radius of the circle inside the square. The side length of the square is the diameter of the circle. Radius is half of the diameter. So, half of 6 cm is 3 cm; this is the radius of the circle.
Third, find the area of the circle by using the formula, A = pi x radius x radius
so, Area = 3.14 x 3 cm x 3 cm
by calculation we get the area of the circle is 28.26 cm^2
Where pi is a constant of 22/7 or 3.14
8 - 4(-2) + 5(6)
8 + 8 + 30
=46
The correct answer here would be D. And that is because, in a triangle, the sum of 2 of the sides has to be greater than the third side for all sides. If we add 22 and 13 we get 35, and 35 is greater than 9, for sure. But if we add 13 and 9 we get 22 which is not greater than the third side length of 22; it would be collinear with the side length and it has to be greater than the side length.
