Log(66)
log(6 × 11)
log(6) + log(11)
6 to the power of 2 is 6 multiplied by six which is 36
then 13 + 39 is 52 - 2 = 50- 10 = 40 - 36= the answer 4
Answer:
C is your answer.
Step-by-step explanation:
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Answer:
a. 54.05 Mpbs.
b. 2.745... standard deviations.
c. The z-score is 2.745....
d. The carrier's highest data speed is significantly high.
Step-by-step explanation:
a. The difference between the highest measured data speed and the mean is 72.6 - 18.55 = 54.05 Mbps.
b. The amount of standard deviations of 54.05 Mbps is equal to this value divided by the standard deviations, so we yield
standard deviations.
c. The z-score is equal to the difference between the mean and a data point in standard deviations, so the z-score is 2.745....
d. 2.745... is not between -2 and 2, so the carrier's highest data speed is not insignificant - so it's significantly high.