Well first 9450/5=1890 then 1890/6= 315 watt hours per day
<span>Traveled Downstream a distance of 33 Mi and then came right back. If the speed of the current was 12 mph and the total trip took 3 hours and 40 minutes.
Let S = boat speed in still water then (s + 12) = downstream speed (s -12) = upstream speed
Given Time = 3 hours 40 minutes = 220 minutes = (220/60) h = (11/3) h Time = Distance/Speed
33/(s +12) + 33/(s-12) = 11/3 3{33(s-12) + 33(s +12)} = 11(s+12) (s -12) 99(s -12 + s + 12) = 11(</span> s^{2} + 12 s -12 s -144) 99(2 s) = 11(s^{2} -144) 198 s/11 = (s^{2} -144) 18 s = (s^{2} -144) (s^{2} - 18 s - 144) = 0 s^{2} - 24 s + 6 s -144 =0 s(s- 24) + 6(s -24) =0 (s -24) (s + 6) = 0 s -24 = 0, s + 6 =0 s = 24, s = -6 Answer) s = 24 mph is the average speed of the boat relative to the water.
Answer:
- Two unique triangles possible
Step-by-step explanation:
Given two sides of 10 cm and one 40° angle
<u>If we use these, we'll get isosceles triangle with:</u>
1. Included 40° angle.
<u>Then the other angles will be same and measure:</u>
2. Adjacent 40° angle. Then one of the angles must be 40° angle as opposite of 10 cm sides.
<u>The remaining angle will measure:</u>
There no more unique triangles possible, so the answer is two.
<span>Simplifying
b4 = 9
Solving
b4 = 9
Solving for variable 'b'.
Move all terms containing b to the left, all other terms to the right.
Simplifying
b4 = 9
Reorder the terms:
-9 + b4 = 9 + -9
Combine like terms: 9 + -9 = 0
-9 + b4 = 0
Factor a difference between two squares.
(3 + b2)(-3 + b2) = 0</span>
