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MAXImum [283]
4 years ago
5

A line passes through (2, −1) and (4, 5). Which answer is the equation of the line?

Mathematics
1 answer:
Tamiku [17]4 years ago
6 0
Y= 3x - 7
subract 5 by -1 which is 6 and divide that by 4-2 which is 2 so 6 divided by 2 is 3. then subtract the y value by 6  to get 0,-7
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Help plz i suck at math
Alex

Answer:

18.75

Step-by-step explanation:

4p - 5 = 70 (add 5 to 70)

4p - 75 (divide 4 and 75)

18.75

4 0
3 years ago
Aye somebody wanna crash my z00m
zheka24 [161]

Answer:

I don't think that's a good idea

Step-by-step explanation:

But I mean if you really want to there's probably a lot of people on here that will

6 0
3 years ago
Read 2 more answers
What is the missing number in the series?<br><br> 1, 16, 81, __, 625, 1296
Alinara [238K]

Answer:

256

Step-by-step explanation:

We are given the series

1, 16, 81, __, 625, 1296

The missing number in the sequence is the fourth term

From the above sequence, we know that

1, 4², 9² , __, 25² , 36²

Difference between first term = 4 - 1 = 3

9 - 4 = 5

x - 9 = 7

x = 9 + 7 = 16

Hence, the fourth term = 16²

= 256

6 0
3 years ago
Find the point-slope equation for the line that passes through the points (5,19) and (-5,-1).
xxTIMURxx [149]

Answer: y - 19 = 2(x - 5)

Step-by-step explanation:

The point slope form is expressed as

y - y1 = m(x - x1)

Where

m represents slope

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

The given points are (5,19) and (-5,-1)

y2 = - 1

y1 = 19

x2 = - 5

x1 = 5

Slope,m = (- 1 - 19)/(- 5 - 5) = - 20/- 10 = 2

To determine the equation, we would substitute x1 = 5, y1 = 19 and m= 2 into the point slope form equation. It becomes

y - 19 = 2(x - 5)

7 0
3 years ago
Read 2 more answers
What is the middle term of the product of (5a - 7)(2a - 1)?
rodikova [14]
(5a-7) (2a-1) = -19a
7 0
4 years ago
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