Answer:

Step-by-step explanation:
![\text{Replace } [-8x] \text{ for } [y]\\\rightarrow [2x+4(-8x)=0]\\\\\text{Solve}\\[2x-32x=0]\\[-30x=0]\\= [0]](https://tex.z-dn.net/?f=%5Ctext%7BReplace%20%7D%20%5B-8x%5D%20%5Ctext%7B%20for%20%7D%20%5By%5D%5C%5C%5Crightarrow%20%5B2x%2B4%28-8x%29%3D0%5D%5C%5C%5C%5C%5Ctext%7BSolve%7D%5C%5C%5B2x-32x%3D0%5D%5C%5C%5B-30x%3D0%5D%5C%5C%3D%20%5B0%5D)
Answer:
Greater than
Step-by-step explanation:
It becomes 8/3
12,000,00+ 400,000+ 30,000
Answer:
7x+5y +29= 0
Step-by-step explanation: first we have to find slop of the line that is.( Y2-Y1)/x2-x1
M = slope = 4+3)/-7+2
M= 7/-5
Equation of line y - y 1 = M (X - X1)
Y+3 = 7/-5 (x+2)
7x + 5y +29 =0 Ans .
We will use integration by substitution, as well as the integrals
∫
1
x
d
x
=
ln
|
x
|
+
C
and
∫
1
d
x
=
x
+
C
∫
x
3
x
2
+
1
d
x
=
∫
x
2
x
2
+
1
x
d
x
=
1
2
∫
(
x
2
+
1
)
−
1
x
2
+
1
2
x
d
x
Let
u
=
x
2
+
1
⇒
d
u
=
2
x
d
x
. Then
1
2
∫
(
x
2
+
1
)
−
1
x
2
+
1
2
x
d
x
=
1
2
∫
u
−
1
u
d
u
=
1
2
∫
(
1
−
1
u
)
d
u
=
1
2
(
u
−
ln
|
u
|
)
+
C
=
x
2
+
1
2
−
ln
(
x
2
+
1
)
2
+
C
=
x
2
2
−
ln
(
x
2
+
1
)
2
+
1
2
+
C
=
x
2
−
ln
(
x
2
+
1
)
2
+
C
Final answer