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sveta [45]
3 years ago
7

I want solution...please help me

Mathematics
1 answer:
Art [367]3 years ago
5 0

sin(<em>θ</em>) + cos(<em>θ</em>) = 1

Divide both sides by √2:

1/√2 sin(<em>θ</em>) + 1/√2 cos(<em>θ</em>) = 1/√2

We do this because sin(<em>x</em>) = cos(<em>x</em>) = 1/√2 for <em>x</em> = <em>π</em>/4, and this lets us condense the left side using either of the following angle sum identities:

sin(<em>x</em> + <em>y</em>) = sin(<em>x</em>) cos(<em>y</em>) + cos(<em>x</em>) sin(<em>y</em>)

cos(<em>x</em> - <em>y</em>) = cos(<em>x</em>) cos(<em>y</em>) - sin(<em>x</em>) sin(<em>y</em>)

Depending on which identity you choose, we get either

1/√2 sin(<em>θ</em>) + 1/√2 cos(<em>θ</em>) = sin(<em>θ</em> + <em>π</em>/4)

or

1/√2 sin(<em>θ</em>) + 1/√2 cos(<em>θ</em>) = cos(<em>θ</em> - <em>π</em>/4)

Let's stick with the first equation, so that

sin(<em>θ</em> + <em>π</em>/4) = 1/√2

<em>θ</em> + <em>π</em>/4 = <em>π</em>/4 + 2<em>nπ</em>   <u>or</u>   <em>θ</em> + <em>π</em>/4 = 3<em>π</em>/4 + 2<em>nπ</em>

(where <em>n</em> is any integer)

<em>θ</em> = 2<em>nπ</em>   <u>or</u>   <em>θ</em> = <em>π</em>/2 + 2<em>nπ</em>

<em />

We get only one solution from the second solution set in the interval 0 < <em>θ</em> < 2<em>π</em> when <em>n</em> = 0, which gives <em>θ</em> = <em>π</em>/2.

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