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3 years ago

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Examine the right triangle. A right triangle with side lengths 17 centimeters and 48 centimeters. The hypotenuse is unknown. Wha

t is the length of the hypotenuse in the right triangle? StartRoot 2,593 EndRoot 60 cm StartRoot 4,225 EndRoot 65 cm

2 answers:

Goshia [24]3 years ago

8 0

Answer:c

Step-by-step explanation:

Dimas [21]3 years ago

5 0

Answer:

The answer to your question is c = $\sqrt{2593}$

Step-by-step explanation:

Data

right triangle

short leg = 17 cm

long leg = 48 cm

hypotenuse = ?

Process

-Use the Pythagorean theorem to find the answer

c² = a² + b²

c = hypotenuse

a = short leg = 17 cm

b = long leg = 48 cm

- Substitution

c² = 17² + 48²

-Simplification

c² = 289 + 2304

c² = 2593

-Result

c = $\sqrt{2593}$

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Trevor solved the system of equations below. What mistake did he make in his work? 2x + y = 5 x − 2y = 10 y = 5 − 2x x − 2(5 − 2

Arturiano [62]

$2x+y=5 \\
x-2y=10 \\ \\
y=5-2x \\
x-2(5-2x)=10 \\
x-10+4x=10 \\
5x-10=10 \\
\boxed{5x=0} \Leftarrow \hbox{the mistake, it should be 5x=20} \\
x=0 \\ \\
2(0)+y=5 \\
y=5$

If 2x+y=5, then y=5-2x, so he substituted 5-2x correctly.
x+4x=5x, so he combined like terms correctly.
If 5x-10=10, then 5x=10+10 -> 5x=20, so he subtracted 10 from the right side instead of adding 10 to the right side.

The answer is C.

Here's the correct solution:
$2x+y=5 \\
x-2y=10 \\ \\
y=5-2x \\
x-2(5-2x)=10 \\
x-10+4x=10 \\
5x-10=10 \\
5x=10+10 \\
5x=20 \\
x=\frac{20}{5} \\
x=4 \\ \\
y=5-2x \\
y=5 - 2 \times 4 \\
y=5-8 \\
y=-3 \\ \\
(x,y)=(4,-3)$

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3 years ago

Find the following:

Butoxors [25]

Answer:

Step-by-step explanation:

Limit refers to the value that the function approaches as the input approaches some value.

We say $\displaystyle \lim_{x\rightarrow a}f(x)=L$ , if f(x) approaches L as x approaches 'a'.

(a)

$\displaystyle \lim_{x\rightarrow 5}\left ( \frac{f(x)-8}{x-5} \right )=4\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-\displaystyle \lim_{x\rightarrow 5}8}{\displaystyle \lim_{x\rightarrow 5}x-\displaystyle \lim_{x\rightarrow 5}5}=4\\$

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$\displaystyle \lim_{x\rightarrow 5}f(x)-8=20-20=0\\\displaystyle \lim_{x\rightarrow 5}f(x)=8$

(b)

$\displaystyle \lim_{x\rightarrow 5}\left ( \frac{f(x)-8}{x-5} \right )=7\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-\displaystyle \lim_{x\rightarrow 5}8}{\displaystyle \lim_{x\rightarrow 5}x-\displaystyle \lim_{x\rightarrow 5}5}=7\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-8}{\displaystyle \lim_{x\rightarrow 5}x-5}=7\\$

$\displaystyle \lim_{x\rightarrow 5}f(x)-8=7\left ( \displaystyle \lim_{x\rightarrow 5}x-5 \right )\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=7\displaystyle \lim_{x\rightarrow 5}x-7(5)\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=7(5)-7(5)\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=35-35=0\\\displaystyle \lim_{x\rightarrow 5}f(x)=8$

3 0

3 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex

velikii [3]

Answer:

The maximum value= 36

Minimum value = - 36

Step-by-step explanation:

Given that

f(x, y, z) = 8 x + 8 y + 4 z

h(x,y,z)=4 x² + 4 y² + 4 z² - 36

From Lagrange multipliers

Δf = λ Δh

Δf = < 8 ,8 , 4>

Δh = < 8 x ,8 y , 8 z>

Δf = λ Δh

So

< 8 ,8 , 4> = < 8 λ x ,8 λ y , 8 λ z>

8 = 8 λ x -------------1

8 = 8 λ y ---- ------2

4 = 8 λ z ----------------3

From equation 1 ,2 and 3

Now by putting the value of x,y and z in the following equation

4 x² + 4 y² + 4 z² = 36

$4\times \dfrac{1}{\lambda^2 }+4\times \dfrac{1}{\lambda^2 }+4\times \dfrac{1}{(2\lambda)^2 }=36$

$\dfrac{4}{\lambda^2 }+ \dfrac{4}{\lambda^2 }+ \dfrac{1}{\lambda^2 }=36$

So the value of λ is

$\lambda =\pm \dfrac{1}{2}$

When λ = 1/2

x = 1 / λ , y=1 / λ , z= 1 /2 λ

x= 2 , y = 2 , z=1

So

f(x, y, z) = 8 x + 8 y + 4 z

f(2, 2, 1) = 8 x 2 + 8 x 2 + 4 x 1

f(2, 2, 1) =36

When λ = - 1/2

x = 1 / λ , y=1 / λ , z= 1 /2 λ

x= - 2 , y = - 2 , z= - 1

So

f(x, y, z) = 8 x + 8 y + 4 z

f(-2, -2, -1) = 8 x (-2) + 8 x (-2) + 4 x (-1)

f(-2, -2, -1) = - 36

The maximum value= 36

Minimum value = - 36

7 0

3 years ago

Read 2 more answers

A baseball team has 4 pitchers, who only pitch, and 16 other players, all of whom can play any position other than pitcher. F

ivolga24 [154]

Answer:

2,075,673,600 batting orders may occur.

Step-by-step explanation:

The order of the first eight batters in the batting order is important. For example, if we exchange Jonathan Schoop with Adam Jones in the lineup, that is a different lineup. So we use the permutations formula to solve this problem.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!}$

First 8 batters

8 players from a set of 16. So

$P_{(16,8)} = \frac{16!}{(16 - 8)!} = 518918400$

Last batter:

Any of the four pitchers.

How many different batting orders may occur?

4*518918400 = 2,075,673,600

2,075,673,600 batting orders may occur.

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3 years ago

Sara and Paul are on opposite sides of a building that a telephone pole fell on. The pole is leaning away from Paul at

r-ruslan [8.4K]

Answer:

a) See figure attached

b) $x = \frac{sin(124)}{sin(34)} 80.086 = 118.732 ft$

c) $h = 35 sin (59) = 30.0 ft$

So then the heigth for the building is approximately 30 ft

Step-by-step explanation:

Part a

We can see the figure attached is a illustration for the problem on this case.

Part b

For this case we can use the sin law to find the value of r first like this:

$\frac{sin(22)}{35 ft} =\frac{sin(59)}{r}$

$r= \frac{sin(59)}{sin(22)} 35 ft = 80.086ft$

Then we can use the same law in order to find the valueof x liek this:

$\frac{sin(124)}{x ft} =\frac{sin(34)}{80.086}$

$x = \frac{sin(124)}{sin(34)} 80.086 = 118.732 ft$

And that represent the distance between Sara and Paul.

Part c

For this cas we are interested on the height h on the figure attached. We can use the sine indentity in order to find it.

$sin (59) = \frac{h}{35}$

And if we solve for h we got:

$h = 35 sin (59) = 30.0 ft$

So then the heigth for the building is approximately 30 ft

5 0

3 years ago