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77julia77 [94]
3 years ago
11

Find the midpoint between -7+4i and 3-2i

Mathematics
1 answer:
lana [24]3 years ago
6 0
(-2,3) i believe this is correct
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I WILL AWARD BRAINLIEST TO THE FIRST PERSON TO ANSWER HONESTLY
ruslelena [56]

Answer:

1,3,5

Step-by-step explanation:

Your first answer is correct,the third one too,and your fifth too.

Hope this helps:)

Pls mark brainlist

3 0
3 years ago
using the giving information to write an equation. let X represent the number described in the exercise.then solve the equation
ANEK [815]
A number is multiplied by 8 and the result is 28.

A number= x.

8(x)= 28

Divide both sides by 8.

28/8= 3.5

x= 3.5 

I hope this helps!
~kaikers
5 0
3 years ago
Evaluate a+4 when a =7
LenaWriter [7]

If a = 7 then a+4 = 11.

a+4 is basically 7+4.

Hope this helps :)

6 0
3 years ago
Read 2 more answers
Please help me I need help please​
MakcuM [25]

Answer:

p = 4

Step-by-step explanation:

Given equation:

x^2+(p-3)y^2-4x+6y-16=0

<u>Standard equation of a circle:</u>

(x-a)^2+(y-b)^2=r^2

(where (a,b) is the centre of the circle, and r is the radius)

If you expand this equation, you will see that the coefficient of y^2 is always one.

Therefore, p-3=1

\implies p=1+3=4

<u>Additional information</u>

To rewrite the given equation in the standard form:

\implies x^2+y^2-4x+6y-16=0

\implies x^2-4x+y^2+6y=16

\implies (x-2)^2-4+(y+3)^2-9=16

\implies (x-2)^2+(y+3)^2=16+4+9

\implies (x-2)^2+(y+3)^2=29

So this is a circle with centre (2, -3) and radius √29

3 0
2 years ago
Literally noone answers my questions please help
prohojiy [21]

Answers:

  • slower train = 139 km per hour
  • faster train = 159 km per hour

=================================================

Explanation:

x = rate of the slower train

x+20 = rate of the faster train

rates are in km per hour, abbreviated as kph

The train traveling at x kph will travel 5x km after 5 hours.

Use this formula

distance = rate*time

Using that same formula, the faster train travels 5(x+20) = 5x+100 kilometers in 5 hours.

The two distances must add to 1490 if we want the trains to pass by each other. Assume that the trains are traveling on parallel side-by-side tracks.

--------------------------

So,

(slower train distance) + (faster train distance) = 1490

(5x) + (5x+100) = 1490

10x+100 = 1490

10x = 1490-100

10x = 1390

x = 1390/10

x = 139

The slower train moves at a rate of 139 km per hour.

x+20 = 139+20 = 159

The faster train moves at a speed of 159 km per hour.

--------------------------

Check:

The slower train travels 139 kph and travels for 5 hours, so it covers a distance of 139*5 = 695 km

The faster train has a speed of 159 kph and travels for 5 hours, so it covers 159*5 = 795 km

Total distance = 695+795 = 1490

The answers are confirmed.

7 0
2 years ago
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