F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Answer:
x < 3
Step-by-step explanation:
2(4+2x)>5x+5
Distribute
8 +4x > 5x+5
Subtract 4x from each side
8 +4x-4x > 5x-4x+5
8 > x+5
Subtract 5 from each side
8-5 > x+5-5
3 > x
X must be less than 3
Answer:
3/10
Step-by-step explanation:
Please give brainliest!
hope this helps :)
the first step is to multiply 1/4 and 2/5
1/4 times 2/5 = 2/20
you figure this out by multiplying the numerators and denominators.
next, we solve 2/20 ÷ 1/3
we do this by taking the reciprocal of 1/3, which is 3/1, and then multiplying the fractions
2/20 times 3/1 = 6/20
6/20 = 3/10
Answer:
4
Step-by-step explanation:
i just did the same test its 4
