Simple.....
you have this fraction...

simplify...
42/6=7
and
60/7=10
Thus...

Thus, she has saved

of the money.
The answer is B) 43<span>°
Angle ADB is an inscribed angle which means arc AB has an angle twice that of angle ADB. The angle of the arc would be the same as that of the central angle AOB. So, mAOB = 86</span>°. And since, mAOB = mBOC, then mBOC = 86° and arc BC has a measure of 86° as well. Angle BDC intercepts the arc BC which means half of the angle of arc BC is mBDC. So, mBDC = 43<span>°.</span>
Answer:
1st box: Asso. prop= m+(4+x)
2nd box: Comm. Prop= m+4=4+m
3rd box: iden. prop= m+0=m
4th box: Zero prop: m x 0=0
Answer:
A
Step-by-step explanation:
The Tangent-Secant Exterior Angle Measure Theorem states that if a tangent and a secant or two tangents/secants intersect outside of a circle, then the measure of the angle formed by them is half of the difference of the measures of its intercepted arcs. Basically, what that means here is that
equals half of the difference of
and the measure of the unlabeled arc.
First, we need to find the measure of the unlabeled arc, since we can't find
without it. We know that the measure of the full arc formed by the circle is
, so the measure of the unlabeled arc must be
by the Arc Addition Postulate.
Now, we can find
. Using all of the information known, we can solve for
like this:

Hope this helps!
Answer:
1. X-intercept is 5 Y-intercept is 4 (Red Line)
2. X-intercept is 1 Y-intercept is 2 (Blue Line)
3. X-intercept is -2 Y-intercept is 4 (Green Line)
Step-by-step explanation:
DESMOS graphing calculator. Here is the graph showing my work: