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Artemon [7]
2 years ago
10

Please help!!!!!!!!!!!!!!!!

Mathematics
1 answer:
aksik [14]2 years ago
6 0

Step-by-step explanation:

< PQS is exterior angle of the triangle

So,

2X = X + 58

X=58

m < P = 58

m <P QR = 180 - ( 58 + 58 ) =, 64

m < P QS = 116

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ikadub [295]
Your question is incomplete can you please elaborate so I can assist you? :)

3 0
3 years ago
A young sumo wrestler decided to go on a special diet to gain weight rapidly. He gained weight at a constar
Masteriza [31]

Answer:

  • <u>5.2 kg per month.</u>

<u></u>

Explanation:

The measure of how fast the wrestler gained weight, in kg per month, is the  weight gain rate.

The table is:

Time (months)           Weight (kg)

    0.5                             80.6

    2                                 88.4

    3.5                              96.2

The weight gain rate, WGR, for a period may be calculated as:

  • WGR = [ weight gain ] / [period]

  • WGR = [final weight - initial weight] / [final time - initial time]

  • WGR₁ = [88.4 kg - 80.6 kg] / [2 month - 0.5 month] = 7.8 kg / 1.5 month = 5.2 kg / month

  • WGR₂ = [96.2 kg - 88.4 kg] / [3.5 month - 2 month] = 7.8 kg / 1.5 month = 5.2 kg / month.

As you see, the wrestler gained weight at a constant rate of 5.2 kg per month.

7 0
3 years ago
According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women
blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

So, Probability of success = 0.75

So, Probability of failure = 1-0.75 = 0.25

If 15 employed women are randomly selected:

a. What is the probability that exactly 2 of them have never been married?

We will use binomial

Formula : P(X=r) =^nC_r p^r q^{n-r}

At x = 2

P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}

P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}

P(X=2) =8.8009 \times 10^{-7}

b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So,  P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}

 P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})

P(X=r) =9.9439 \times 10^{-6}

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=0.2360

8 0
3 years ago
QUICK QUESTION! PLEASE ANSWER FAST!
mr_godi [17]
A^2 + B^2 = C^2
7^2 + B^2 = 25^2
49 + B^2 = 625
-49 -49
B^2 = 576
Square root both sides
B = 24
4 0
3 years ago
Read 2 more answers
Show all work to write the expression in simplified radical form:
Gekata [30.6K]

Answer:0.08333333....

Step-by-step explanation:

8 0
1 year ago
Read 2 more answers
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