Answer:
The answer to your question is: 5 bottles
Step-by-step explanation:
Process
First week
Divide 24 by 8
24/8 = 3 bottles = 1/8
but Sanjay drank 3/8 = 9 bottles
And there are 24 - 9 bottles left = 15
- Second week
Divide 15 by 3
15/3 = 5 then 5 bottles = 1/3
but sanjay drank 2/3 = 10 bottles
Then, there are 15 - 10 bottles left = 5
The answer is <span>She went over by one over six of a cup
</span>
<span>1 cup of that particular chocolate powder has a mass of 128 grams: 1c = 128g
</span><span>64 grams of chocolate powder is x cups.
1c = 128g
x = 64g
1c : 128 g = x : 64g
x = </span>1c : 128 g * 64 g
x = 0.5 c
64 grams of chocolate powder is 0.5 cups = 1/2 cups
<span>She added two over three of a cup of chocolate powder: 2/3 cups
She need to add 1/2 cups: 1/2 = 3/6 cups
She added 2/3 cups: 2/3 = 4/6 cups
So she added 4/6 - 3/6 = 1/6 cups more.
</span>
Answer is A.Rational number
Answer:

Step-by-step explanation:





For the Interval 
Length of the Curve 
Using T1-Calculator

This is my work hope this helps.