All categories

3 years ago

The period is.......

Mathematics

1 answer:

Leni [432]3 years ago

7 0

<h3>Answer: 2.244 seconds</h3>

Explanation:

The x coordinate of the left peak point is x = 1.870, and its neighboring peak point has an x coordinate of x = 4.114

The difference is 4.114 - 1.870 = 2.244

The period is 2.244 seconds, which is the time it takes to go from one peak to another adjacent. This is the same as going from one valley point to a neighboring valley point.

You might be interested in

On the first day of school bethanys family donated $60 to the field trip fundraiser. what percent of their goal did bethanys fam

Romashka-Z-Leto [24]

Answer:

Step-by-step explanation:

Got it right on edge, plz mark brainliest

7 0

3 years ago

Read 2 more answers

Which expression converts 4pi radians to degrees?

grin007 [14]

4pi/2pi = x/360
use a proportion
2 radians equals 360 degrees
x = 720 degrees

7 0

3 years ago

Read 2 more answers

When 2/3 is added to a certain number, the sum is 3 greater than twice the number. part 1: set up an equation using n to represe

Gennadij [26K]

2/3 + n = 2n + 3 <== ur equation
2/3 - 3 = 2n - n
2/3 - 9/3 = n
-7/3 = n <== ur solution

or
2/3 + n = 2n + 3...multiply everything by common denominator of 3
2 + 3n = 6n + 9
2 - 9 = 6n - 3n
-7 = 3n
-7/3 = n

7 0

2 years ago

Find f(-1) if f(x) = -2x^2 -x

kykrilka [37]

I hope it was helpful to you

if u like follow me

3 0

2 years ago

One more time!

CaHeK987 [17]

Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

$\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}$

so we conclude that
$q(\frac{\sqrt{19} }{2} ) = 1/4$

therefore

$p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right) \right)$

plug $x=\sqrt{19}/2$ into p( q(x) ) to get answer

$p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left( \frac{\sqrt{19} }{2}\right)^2 }{ \left( \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow$

$\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow -\dfrac{6\sqrt{19} }{361}$

$p(1/4) = -\dfrac{6\sqrt{19} }{361}$

3 0

2 years ago