Let us assume that the number of alternative schools in the county are x in number.
It is given that the number of charter schools is 4 less than twice the number of alternative schools. So we can write, the number of charter schools is 4 less than twice of x. In equation form this can be written as:
Number of Charter Schools = 2x - 4
It is given that number of charter schools is 48. So we can write:
48 = 2x - 4
2x = 52
x = 26
x was the number of alternative schools. Therefore, there are 26 alternative schools in the county.
maybe a hundred or a thousand years idk so maybe 500 i dont actually know
(n-6)*2=2
or i think it can be (6-n)*2=2
Answer:
W = 16
L = 24
Step-by-step explanation:
Let's write down the information we have first
"The length of a rectangle is 8 feet longer than it is wide"
L = W + 8
"If each side is increased 8 feet, then the area is multiplied by 2."
(L + 8)(W + 8) = 2LW
Now we can solve for W first, then L
(W + 16)(W + 8) = 2W(W + 8)
W² + 24W + 128 = 2W² + 16W
0 = W²- 8W - 128
0 = (W - 16)(W + 8)
W = 16
L = 24
(This part above is solved like quadratics)
Answer:
4
Step-by-step explanation:
1. 7(10-3)
7×7
49
2. 70-3
67
3. 5+20-3
25-3
22
4.5+2(7)
5+14
24
5+2(10-3)
5+2×7
5+14
24
