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Kisachek [45]
3 years ago
15

In certain county, the number of charter schools is 4vless than twice the numbervof alternative schools. We know that there are

48 charter schools in the county. How many alternative schools are in the county?
Mathematics
2 answers:
Kay [80]3 years ago
5 0
Let us assume that the number of alternative schools in the county are x in number.

It is given that the number of charter schools is 4 less than twice the number of alternative schools. So we can write, the number of charter schools is 4 less than twice of x. In equation form this can be written as:

Number of Charter Schools = 2x - 4

It is given that number of charter schools is 48. So we can write:

48 = 2x - 4
2x = 52
x = 26

x was the number of alternative schools. Therefore, there are 26 alternative schools in the county.
Rzqust [24]3 years ago
5 0
1. Let's call the number of carter school: "x" and "y" the number of alternative school.  Then, you have that: 
 - T<span>he number of charter schools is 4 less than twice the number of alternative schools.
</span> - T<span>here are 48 charter schools in the country.
 2. So, you have:
 x=2y-4  (i)
 x=48  (ii)
 3. Then, when you substitute x=48 into the equation (i), you obtain:
</span> x=2y-4
<span> 48=2y-4
 4. Now, you must clear "y, as below:
 48+4=2y
 2y=52
 y=52/2
 y=26
</span><span>
 How many alternative schools are in the county? </span><span>The answer is: There are 26 alternative schools.</span>
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<u>Answer: </u>

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\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1

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