Let us assume that the number of alternative schools in the county are x in number.
It is given that the number of charter schools is 4 less than twice the number of alternative schools. So we can write, the number of charter schools is 4 less than twice of x. In equation form this can be written as:
Number of Charter Schools = 2x - 4
It is given that number of charter schools is 48. So we can write:
48 = 2x - 4 2x = 52 x = 26
x was the number of alternative schools. Therefore, there are 26 alternative schools in the county.
1. Let's call the number of carter school: "x" and "y" the number of alternative school. Then, you have that: - T<span>he number of charter schools is 4 less than twice the number of alternative schools. </span> - T<span>here are 48 charter schools in the country. 2. So, you have: x=2y-4 (i) x=48 (ii) 3. Then, when you substitute x=48 into the equation (i), you obtain: </span> x=2y-4 <span> 48=2y-4 4. Now, you must clear "y, as below: 48+4=2y 2y=52 y=52/2 y=26 </span><span> How many alternative schools are in the county? </span><span>The answer is: There are 26 alternative schools.</span>
