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Mila [183]
3 years ago
7

If sin tetha=root3/2, what is cos tetha?​

Mathematics
1 answer:
Minchanka [31]3 years ago
6 0

Answer:

The value of cos Ф is ± \frac{1}{2}

Step-by-step explanation:

There are important rules for sin Ф and cos Ф

  • sin²Ф + cos²Ф = 1
  • sin²Ф = 1 - cos²Ф
  • cos²Ф = 1 - sin²Ф

∵ sin Ф = \frac{\sqrt{3}}{2}

∴ sin²Ф = (\frac{\sqrt{3}}{2})^{2}

∴ sin²Ф = \frac{3}{4}

→ By using the third rule above

∵ cos²Ф = 1 - sin²Ф

∴ cos²Ф = 1 - \frac{3}{4}

∴ cos²Ф = \frac{1}{4}

→ Take square root for both sides

∴ cos Ф = ± \frac{1}{2}

∴ The value of cos Ф is ± \frac{1}{2}

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The five-number summary is:

Minimum: 9

First Quartile: 16.5

Median: 25.5

Third Quartile: 39

Maximum: 51

3. Range = 42

4. Interquartile range = 22.5

<h3>How to Find the Five-number Summary of a Data?</h3>

Given the data for the lengths as, 36, 15, 9, 22, 36, 14, 42, 45, 51, 29, 18, 20, to find the five-number summary of the data set, we would follow the steps below:

1. The numbers in ordered from the smallest to the largest would be:

9, 14, 15, 18, 20, 22, 29, 36, 36, 42, 45, 51

2. The five-number summary for the lengths in minutes would be:

  • Minimum value: this is the smallest lengths, which is 9
  • First Quartile (Q1): this is the middle of the first half of the data set of the lengths in minutes, which is 16.5.
  • Median: the median is the center of the data distribution which is 25.5.
  • Third Quartile: this is the middle of the second half of the data set of the lengths in minutes, which is 39.
  • Maximum: this is the largest length in minutes, which is, 51.

3. Range of the data = max - min = 51 - 9 = 42

4. The interquartile range for the data set = Q3 - Q1 = 39 - 16.5

Interquartile range for the data set = 22.5

Learn more about the five-number summary on:

brainly.com/question/24809873

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Please help___________​
kramer

Answer:

Step-by-step explanation:

Let's do the obvious things first.

Right rectangle

w = 11

L = 17

Formula

Area = L * W

Area = 11 * 17

Area =                                                187

Left rectangle

W = 8

L = 11

Area = 8 * 11=                                      88

Middle Rectangle

W = 11

L = 15

Area = 11 * 15                                    165

Now we come to the triangles. It's not obvious what to do with them. You have to infer that one of the lets is 8 and the other is 15. You get the 8 from the width of the left rectangle (see above.)

There are 2 triangles

Area = 2 * 1/2 * l1 * l2

Leg 1 = 8

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Area = 2 * 1/2 (8 * 15)

Area =               <u>                            120 </u>

Total  = 120 + 165 + 88 + 187 =    560

Unless you have an  E answer that is 560, my answer does not agree with any of the given answers. I would suggest that you ask your teacher how it is done. My method is correct.

4 0
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