Michael took the return trip at a velocity 33.75 miles per hour.
<h3>How fast did Michael drive in his return trip?</h3>
Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.
First trip
45 = s / 3 (1)
Second trip
v = s / 4 (2)
By (1) and (2):
45 · 3 = 4 · v
v = 33.75 mi / h
Michael took the return trip at a velocity 33.75 miles per hour.
To learn more on velocities: brainly.com/question/18084516
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X= 5 or -8
Add all the like terms and set it equal to 49, use quadratic formula or factoring.
It’s in Quadrant I. Because it’s not on the origin and it doesn’t fall on any of the axis
Answer: .1.) 28.8
9.) 150 ft
8.) 630 ft
10.) 5'10"
Step-by-step explanation:. Ratios set up as fractions. 12/25 :x/60
cross multiply. 12 × 60 = 720. Divide by denominator if left side.
720/25 = 28.88
