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noname [10]
2 years ago
14

‼️‼️‼️‼️HELP‼️‼️‼️‼️‼️‼️‼️

Mathematics
1 answer:
Vesnalui [34]2 years ago
3 0

Michael took the return trip at a velocity 33.75 miles per hour.

<h3>How fast did Michael drive in his return trip?</h3>

Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.

First trip

45 = s / 3     (1)

Second trip

v = s / 4       (2)

By (1) and (2):

45 · 3 = 4 · v

v = 33.75 mi / h

Michael took the return trip at a velocity 33.75 miles per hour.

To learn more on velocities: brainly.com/question/18084516

#SPJ1

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What is the simplified form of the following expression?
USPshnik [31]

Option C:

$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}

Solution:

Given expression is

$\sqrt[3]{\frac{4 x}{5}}

Note: \sqrt[3]{125}=\sqrt[3]{{5^3}}  = 5

To find the correct expression for the above simplified expression.

Option A: \frac{\sqrt[3]{4 x}}{5}

5 can be written as \sqrt[3]{125}.

$\frac{\sqrt[3]{4 x}}{5}=\frac{\sqrt[3]{4 x}}{\sqrt[3]{125} }

       $=\sqrt[3]{\frac{4x}{125} }

It is not the given simplified expression.

Option B: \frac{\sqrt[3]{20 x}}{5}

$\frac{\sqrt[3]{20 x}}{5}=\frac{\sqrt[3]{20 x}}{\sqrt[3]{125} }

         $=\sqrt[3]{\frac{20x}{125} }

Cancel the common factor in both numerator and denominator.

         $=\sqrt[3]{\frac{4x}{25} }

It is not the given simplified expression.

Option C: \frac{\sqrt[3]{100 x}}{5}

$\frac{\sqrt[3]{100 x}}{5}=\frac{\sqrt[3]{100 x}}{\sqrt[3]{125} }

           $=\sqrt[3]{\frac{100x}{125} }

Cancel the common factor in both numerator and denominator.

           $=\sqrt[3]{\frac{4 x}{5}}

It is the given simplified expression.

Option D: \frac{\sqrt[3]{100 x}}{125}

$\frac{\sqrt[3]{100 x}}{125}=\frac{\sqrt[3]{100 x}}{5^3}

It is not the given simplified expression.

Hence Option C is the correct answer.

$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}

3 0
3 years ago
A plane descends 1000 ft while flying<br> 2.7 mi. What is the angle of descent?
Murrr4er [49]

Answer:

4.02°

Step-by-step explanation:

The angle of descent can be obtained using trigonometry ;

Since we have a right angled triangle ;

Let's use the relation:

Sin θ = opposite / hypotenus

Hypotenus = 2.7 miles

1 mile = 5280 feets

2.7 miles = (2.7 * 5280) = 14256 feets

Sin θ = 1000 / 14256

Sin θ = 0.0701459

θ = sin^-1(0.0701459)

θ = 4.0223674

3 0
3 years ago
1. Find the Surface Area of the rectangular prism. Show your work and explain how you solved using First,
mafiozo [28]

Answer:

376 inches^2

Step-by-step explanation:

<h3>1. Divide up each type of rectangle </h3>

- 10x6

- 6x8

- 8x10

<h3>2. Find the area of each rectangle</h3>

- 10x6=60

- 6x8=48

- 8x10=80

<h3>3. Multiply each rectangle by two to get the opposite one</h3>

- 60x2=120

- 48x2=96

- 80x2=160

<h3>4. Add them together</h3>

120+96+160=376

The surface area is 376 inches^2

6 0
2 years ago
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