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Mama L [17]
3 years ago
9

Which of the following options is a counterexample that proves the given conditional statement false?

Mathematics
2 answers:
mash [69]3 years ago
7 0
If a number is divisible by ten, then it is divisible by four, the counter example is 10 because you can't divide it by 4 and get a whole number, unlike the other choices. 
Delvig [45]3 years ago
5 0

Answer:

Counter example to prove the statement "If a number is divisible by ten, then it is divisible by four" false is:

10

Step-by-step explanation:

We are given a statement:

"If a number is divisible by ten, then it is divisible by four. "

We have to find the counter example to prove the following statement wrong.

10 is divisible by ten

then, according to the above statement it must also be divisible by four

but 10 is not divisible by four

Hence, Counter example to prove the statement "If a number is divisible by ten, then it is divisible by four" false is:

10

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PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!! I NEED TO FINISH THESE QUESTIONS BEFORE MIDNIGHT TONIGHT.
Paul [167]

Answer:

Step-by-step explanation:

Triangle WXY is a right angle triangle.

From the given right angle triangle

WY represents the hypotenuse of the right angle triangle.

With ∠W as the reference angle,

WX represents the adjacent side of the right angle triangle.

XY represents the opposite side of the right angle triangle.

To determine WY, we would apply the Sine trigonometric ratio

Sin θ = opposite side/hypotenuse. Therefore,

Sin 36 = 5/WY

WY = 5/Sin36 = 5/0.5878

WY = 8.5 to the nearest tenth

3 0
4 years ago
What is the area of Shaded part?
svetlana [45]

Answer:

1π

Step-by-step explanation:

suppose the radius of semicircle P is r,

then the radius of semicircle Q = (r+d)/2  ... d≤r

radius of semicircle R = (r-d)/2

area P = 1/2 (r)²π

area Q = 1/2 ((r+d)/2)² π = 1/8 (r² + 2rd + d²)π

area R = 1/2 ((r-d)/2)² π = 1/8 (r² - 2rd + d²)π

shaded area = P-Q-R = 1/2 r²π - 1/4 (r² + d²)π

                                   = ((r² - d²)/4) * π

because there is no constant r value in the question and d value changes with the r change, when the vertical segment length equal the semicircle P radius (r), r=2 and d = 0

therefore the shaded area = ((2² -0²)/4)*π = 1π

8 0
3 years ago
Select all the equations for which (-6,-1) is a solution. *
ella [17]
1 and 4 hope this helps!
8 0
3 years ago
Solving polynomial(2y-4)(3y+6)​
jeka57 [31]

Answer:

6y² - 24

Step-by-step explanation:

Expand. Follow FOIL method. FOIL =

First

Outside

Inside

Last.

First, multiply the first term of each parenthesis:

2y * 3y = 6y²

Next, multiply the outside terms from both parenthesis:

2y * 6 = 12y

Then, multiply the inside terms from both parenthesis:

-4 * 3y = -12y

Finally, multiply the last terms of each parenthesis:

-4 * 6 = -24

Combine like terms:

6y² + 12y - 12y - 24

6y² + (12y - 12y) - 24

6y² - 24

6y² - 24 is your answer.

~

3 0
4 years ago
Read 2 more answers
A diagram of a swimming pool is below. The width of the pool is 25 m, find the length of the actual pool?
lara [203]

Answer:50

Step-by-step explanation:

7.5 x 2 = 15

25 x 2 = 50

8 0
3 years ago
Read 2 more answers
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