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Vlad1618 [11]
3 years ago
6

I need help on this question

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
5 0

The combined number of AB patients is 33.

The total number of patients is 714.

To find what percent a part is of a total, divide the part by the total and multiply by 100. Here, the part is 33. The total is 714.

33/714 * 100 = 0.0462 * 100 = 4.62%

Answer: D. 4.6%

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Mr. Clark sold 280 bags of chips and 415 bottles of juice in 5 days. At this rate, Mr. Clark will sell_________ bottles of juice
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Answer:

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Step-by-step explanation:

Because in 5 days he did 415 bottle in 12 it will be 996.

5 0
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Riley paid $2.99 for a 20-ounce container of soup. at that rate, what would riley pay for a 12-ounce container of the same soup?
love history [14]
$2.99/20 will be the unit price of soup. Then the amount Riley has to pay for 12 ounce would be 12*2.99/20=$1.794
8 0
3 years ago
What is 7 over (fraction bar) (8×4)+90÷9 ÷ (6^3)^-2 × 9 over (fraction bar) 6(5+4) = ?????
amid [387]
The answer is:  " 36 " .
_______________________________
Note:  " (8 * 4) + 90 ÷ 9 " =  " (8 * 4) + (90 ÷ 9) " = "32 + 10 = 42" .

We can rewrite the "fraction":
 
7 / [ (8 * 4) + 90 ÷ 9 ] ;  as:  \frac{7}{42} ;  

and can reduce this value to (and rewrite as):  " \frac{1}{6} " ; 
    { since:  " \frac{7}{42}  =  \frac{7/7}{42/7}  = \frac{1}{6}" .}.

Note:  The "fraction" : \frac{9}{6(5+4)} ;  the "9/6" cancel to "3/2" ; 
  {Since:  "9÷3 = 3" ; and since:  "6÷3 = 2" ).

So rewrite:  \frac{9}{6(5+4)} ; as:  

\frac{3}{2(5+4)} ;

Note:  \frac{3}{2(5+4)}  ;

       =   \frac{3}{2(9)} ;

       =   \frac{3}{18} ;

→  Note:   \frac{3}{18} ;  can be reduced to; & rewritten as:

             " \frac{1}{6} " ;

→ {since: " \frac{3}{18} =  \frac{3/3}{18/3} ;
               
                                                      =   \frac{1}{6} ;
______________________________

Note that: (6²) ⁻² = 6⁽ ² * ⁻²⁾ = 6⁻ ⁴  ;
    
                            =  \frac{1}{6^4} ;
_________________________________________________________
So, we can rewrite our expression as:

 \frac{1}{6}  ÷  \frac{1}{6^4}  *  \frac{1}{6} ;
_________________________________________________________
Note:  
_________________________________________________________
 \frac{1}{6}  ÷  \frac{1}{6^4}  *  \frac{1}{6} ;

= ( \frac{1}{6}  ÷  \frac{1}{6^4} ) *  \frac{1}{6} ; 

= ( \frac{1}{6}  *   \frac{6^4}{1} ) *  \frac{1}{6} ;

________________________________________________________
Start with :
________________________________________________________
   → ( \frac{1}{6}  *   \frac{6^4}{1} ) ;

            The "6" in  the  " \frac{1}{6} " ;  cancels to a "1" ; 
       and the "6⁴ " in the "  \frac{6^4}{1} ) " ; cancels to a "6³ " ;

         → {Since:  "6⁴ / 6  =  6⁴ / 6¹  =  6⁽⁴ ⁻ ¹⁾  = 6³ ;

         → and we have:   \frac{1}{1}  *  \frac{6^3}{1} ;
 
         →  The " \frac{1}{1} " can be eliminated; since "1÷1= 1 " ;
               and since: any value, divided by "1", equal that same value; & since "any                       value, multiplied by "1"; equals that same value" ;
________________________________________________________
 We have:  " 6³ " .
________________________________________________________

Now, we multiplied this value, " 6³ " , by  " \frac{1}{6} " ;

→  6³  *  \frac{1}{6}  ;

     =  \frac{6^3}{1} * \frac{1}{6}  ;

Note:  The "6³ " cancels out to "6² " ;  and the "6" cancels out to "1" ; 

          {since:  "6³ ÷ 6 = 6³ ÷ 6¹ = 6⁽³ ⁻ ¹⁾ = 6² " ;
            and since:  "6 ÷ 6 = 1 "  ; ________________________________________________________
→ The answer is:  6² = 6 * 6 = 36 ;
________________________________________________________
The answer is:  " <span>36 " .</span>
________________________________________________________
7 0
3 years ago
Find the IQR of the data set
Phoenix [80]
Find median, in this group median is 1
 find Q1 which is median of lower half, in this group Q1 = 1/4

find Q3, which is median of upper half, in this group Q3 = 5/4

IQR is Q3-Q1

IQR = 5/4 - 1/4 = 4/4 = 1



5 0
3 years ago
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