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Vitek1552 [10]
3 years ago
13

Which transformation will occur if f(x)=x is replaced with f(x) +5

Mathematics
1 answer:
zimovet [89]3 years ago
7 0

Answer:

Parent function f(x) = x with f(x)+5 means the parent function will vertically shift 5 units up.

Step-by-step explanation:

<u>Vertical translation of f(x) is of the form</u>

f(x)+k

It means if the constant 'k' is added in the output, the parent graph vertically shifted 'k' units up.

Given

f(x)=x

Replacing the parent function f(x) = x with f(x)+5 means the parent function will vertically shift 5 units up.

Please also check the attached diagram.

  • The red graph shows the parent function i.e. f(x)=x
  • The blue graph shows the transformed function i.e. f(x)+5

The blue graph is the result of the vertically shifting of the parent function by 5 units up.

Hence, parent function f(x) = x with f(x)+5 means the parent function will vertically shift 5 units up.

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alisha [4.7K]
10 to 1
20 to 2 or something like that
8 0
4 years ago
Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,
torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

y=6x^2+14x

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

\frac{dy}{dx}=12x+14

We know that length of curve

s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx

We have a=-2 and b=1

Using the formula

Length of curve=s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

dt=12dx

dx=\frac{1}{12}dt

Length of curve=s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt

We know that

\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C

By using the formula

Length of curve=s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})

Length of curve=s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})

Length of curve=s=32.66

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=6%20%5Cdiv%207.74%20%3D%20" id="TexFormula1" title="6 \div 7.74 = " alt="6 \div 7.74 = " align
Liula [17]
6 \div 7.74 = \dfrac{6}{7.74}=\dfrac{6\cdot100}{7.74\cdot100}=\dfrac{600}{774}=\dfrac{600:2}{774:2}=\dfrac{300:3}{387:3}=\dfrac{100}{129}
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3 years ago
Which explains how to determine 40% out of 50
Nikolay [14]

Answer:

20

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Step-by-step explanation:

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How do you determine where an irrational number is located on a number line
zmey [24]

Answer:

Step-by-step explanation:

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4 years ago
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