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madreJ [45]
3 years ago
15

Given: ∠ABC is a right angle and ∠DEF is a right angle. Prove: All right angles are congruent by showing that ∠ABC ≅∠DEF. What a

re the missing reasons in the steps of the proof?
Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
8 0

A. definition of right angle

B. substitution property

C. definition of congruent angles

balu736 [363]3 years ago
6 0

Answer:

A. definition of right angle

B. substitution property

C. definition of congruent angles

Step-by-step explanation:

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If I had $33,50 last month and this month I got a raise and brought back $45,70 how much more did I bring back
Effectus [21]

You brought back 12.2

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5 0
3 years ago
Solve for X <br><br>Explain if possible :)
sweet-ann [11.9K]

The two labeled angles are alternate interior angles, and as such, they are the same.

From this result you can build the equation

15x-2 = 13x+2

and solve it for x: subtract 13x from both sides to get

2x-2=2

and add 2 to both sides to get

2x = 4 \implies x = 2

Check: if we plug the value we found we have

13\cdot 2 + 2 = 26+2 = 28 = 15\cdot 2 - 2 = 30-2

So the angles are actually the same, as requested.

4 0
3 years ago
What is the value of this expression?<br> 49 - (11 – 4)
Illusion [34]

Answer:

42

Step-by-step explanation:

11 - 4 = 7

49 - 7 = 42

3 0
3 years ago
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Answer:

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Step-by-step explanation:

4 0
3 years ago
Write the equation of the line in fully simplified slope-intercept form.
Lina20 [59]

Answer:

y=-6x+2

Step-by-step explanation:

Hi there!

Slope-intercept form: y=mx+b where <em>m</em> is the slope and <em>b</em> is the y-intercept (the value of y when x=0)

<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>

m=\displaystyle \frac{y_2-y_1}{x_2-x_1} where two points that fall on the line are (x_1,y_1) and (x_2,y_2)

Given the graph, we determine which points we could use. For example, we could use the two points (0,2) and (1,-4):

m=\displaystyle \frac{-4-2}{1-0}\\\\m=\displaystyle \frac{-6}{1}\\\\m=-6

Therefore, the slope of the line is -6. Plug this into y=mx+b:

y=-6x+b

<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>

Recall that the y-intercept occurs when x=0. Given the point (0,2), we know that the y-intercept is 2. Plug this into y=-6x+b:

y=-6x+2

I hope this helps!

5 0
3 years ago
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