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3 years ago

PLEASE HELP I WILL GIVE BRAINLEIST PLEASE ALSO SHOW STEPS!!!!!!

Mathematics

1 answer:

julia-pushkina [17]3 years ago

4 0

Answer:

The equation of a line that passes through the point (-1,5) and has a slope of -7 will be:

y = -7x-2

Step-by-step explanation:

The slope-intercept form of the line equation

$y = mx+b$

where

m is the slope

b is the y-intercept

Given

The point (-1, 5)

Slope m = -7

substituting m = -7 and the point (-1, 5) in the slope-intercept form of the line equation

$y = mx+b$

5 = -7(-1) + b

5 = 7+b

b = 5-7

b = -2

Thus, the y-intercept is: b = -2

now substituting b = -2 and m = -7 in the slope-intercept form of the line equation

y = mx+b

y = -7x+(-2)

y = -7x-2

Therefore, the equation of a line that passes through the point (-1,5) and has a slope of -7 will be:

y = -7x-2

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when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.

sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = $a^2$

6 is subtracted from the square of a number = $a^2 - 6$

5 times the number = $5 \times a$

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

$a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0$

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation $ax^2 + bx + c = 0$ where $a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in this problem,

$a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6$

Substituting the values in above quadratic formula, we get

$\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}$

We have two solutions for "a"

$\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}$

We have asked negative solution. So a = -1

Thus the negative solution is -1

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For x = -1

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