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GenaCL600 [577]
3 years ago
7

Please help and do problems 6, 7 and 8 for me thank you :)

Mathematics
1 answer:
Arturiano [62]3 years ago
6 0
Use formula : Y-y1=m(x-x1)
(x1,y1) = the points given in each situation

6. Y-0=1(x-2)
Y=x-2 or x-y-2=0

7. Y-(-1)= -1/3(x-(-3))
Y+1= -1/3x + 1
3y=-x or x+3y=0

8.Y-4=3(x-5)
Y-4= 3x - 15
Y=3x -11 or 3x-y-11=0
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There are 40 pupils in a class. 75% of them are present. How may are present? How many are absent?
Aleonysh [2.5K]

Answer:

30 are present 10 are absent

Step-by-step explanation:

75%=3/4

so 3/4 of them are absent

3/4(40)=30

and 40-30=10 are absent

8 0
2 years ago
Nicole is making 1,000 bows for people who donate to the library book sale. She needs a piece of ribbon that is 0.75 meter long
Natasha2012 [34]
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3 years ago
Solve.
Aloiza [94]

Step-by-step explanation:

x=−y−2z+3

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8 0
3 years ago
Circle A has a diameter of approximately 20 inches and an area of approximately 300 in2.
Katena32 [7]

Answer:

4. About 2,700 in2

Step-by-step explanation:

The area of a circle (A), measured in square inches, is directly proportional to the square of its diameter (d), measured in inches. That is:

A \propto d^{2}

A = k\cdot d^{2}

Where k is the constant of proportionality, dimensionless.

In consequence, the following relationship between circles A and B is obtained:

\frac{A_{B}}{A_{A}} = \frac{d_{B}^{2}}{d_{A}^{2}}

The area of the circle B is now cleared:

A_{B} =\left(\frac{d_{B}}{d_{A}} \right)^{2}\cdot A_{A}

Given that d_{A} = 20\,in, d_{B} = 60\,in and A_{A} = 300\,in^{2}, then:

A_{B} = \left(\frac{60\,in}{20\,in} \right)^{2}\cdot (300\,in^{2})

A_{B} = 2700\,in^{2}

Therefore, the correct answer is 4.

7 0
3 years ago
Please help need it due now!!!
ahrayia [7]

Answer:

1) 0.9, 0.99, 0.09, 0.0009

2) 4(2x²+9x)

3) 110

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2 years ago
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