can you tell me what the points are because the graph is somewhat blurry
Answer:
Step-by-step explanation:
y = -x + 7 -------------(II)
Plugin y = -x + 7 in equation (I)
2(-x + 7) =x² - 6x + 9
-2x + 14 =x ² - 6x + 9
x² - 6x + 9 = -2x + 14
x² - 6x + 9 + 2x - 14 = 0
x² - 4x - 5 = 0
x² -5x + x - 5 = 0
x(x - 5) + 1(x - 5) = 0
(x -5)(x + 1) = 0
x- 5 = 0 ; x + 1 = 0
x = 5 ; x = -1
When x = 5 ⇒ y = -5 + 7 = 2
When x = -1 ⇒ y = -(-1) + 7 = 1 + 7 = 8
Solution (5 , 2) & (-1 , 8)
Answer:
Distance between the points Q and R is 1 unit while the distance between the points R and S is 3 units
Step-by-step explanation:
Here, we want to use the absolute value of the coordinates to find the distances.
Since we are using absolute values, the negative points becomes positive;
Thus;
Q = (4,2)
R = (3,2)
S = (3,5)
Mathematically, the distance between two points in the Cartesian plane can be calculated using the formula;
D = √(x2-x1)^2 + (y2-y1)^2
The distance QR is thus;
D = √(3-4)^2 + (2-2)^2
D = √(-1)^2 + 0
D = √1 = 1 unit
The distance RS is thus;
D = √(3-3)^2 + (5-2)^2
D = √(0) + (9)
D = √9 = 3 units
Answer:
(x , y ) ---> (x + 6 , y - 3)
Step-by-step explanation:
(x , y ) ---> (x + 6 , y - 3)
P(-1 , 4) -----> P'(-1+6 , 4-3) = P'(5,1)
Comapre P and P' x-coordinate
-1 + a = 5
a = 5 +1 = 6
Q(-1, 2) ----->Q'(-1+6 , 2 -3)= Q'(5, -1)
R(3 , 1) ------> R'(3+6 , 1-3) = R'(9,-2)
