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Katyanochek1 [597]
3 years ago
14

Help me with area, please.

Mathematics
1 answer:
nikdorinn [45]3 years ago
4 0

Answer:

Num. 2: A = 25, Num. 3 = 63, Num. 4 = 80

Step-by-step explanation:

I'll help with as many as I can, so a few of them I won't be able too answer. You should re-post those later. Good luck, hope this helps.

For number 2:

First, turn the triangle into a rectangle by cutting it in half and attaching it to the other half so it forms a rectangle.

Since you cut the triangle in half, you also have to split 5 in half, so the bottom length is now 2.5.

Now, simply multiply 2.5 by 10, and you have the area for number 2.

The area for number 2 is 25.

For number 3:

This one is much easier. Just think of the shape as a normal square that has been tipped to the side. That means that you would solve for area the same way: 9 x 7, which means that the area for number 3 is 63.

For number 4:

This one is also easy. Simply cut, and paste. Now the right side is 10, and the top side is 8. Multiply, and the area will be 80 m.

Please re-post 1 and 5, as I am not able to solve them. Sorry this answer took so long!

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3 years ago
The price of a television was reduced from $250 to $200. By what percentage was the price of the television reduced?
gavmur [86]

Answer: C

Step-by-step explanation:Well the change in price was 50 dollars

Now divide your change in price by the original price

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6 0
3 years ago
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Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a seco
kari74 [83]

Answer:

C. \frac{1}{18}

Step-by-step explanation:

Given: Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl then a second card is drawn.

To Find: If the cards are drawn at random and if the sum of the numbers on the cards is 8, what is the probability that one of the two cards drawn is numbered 5.

Solution:

Sample space for sum of cards when two cards are drawn at random is \{(1,1),(1,2),(1,3)......(6,6)\}

total number of possible cases =36

Sample space when sum of cards is 8 is \{(3,5),(5,3),(6,2),(2,6),(4,4)\}

Total number of possible cases =5

Sample space when one of the cards is 5 is \{(5,3),(3,5)\}

Total number of possible cases =2

Let A be the event that sum of cards is 8

p(\text{A}) =\frac{\text{total cases when sum of cards is 8}}{\text{all possible cases}}

p(\text{A})=\frac{5}{36}

Let B be the event when one of the two cards is 5

probability than one of two cards is 5 when sum of cards is 8

p(\frac{\text{B}}{\text{A}})=\frac{\text{total case when one of the number is 5}}{\text{total case when sum is 8}}

p(\frac{\text{B}}{\text{A}})=\frac{2}{5}

Now,

probability that sum of cards 8 is and one of cards is 5

p(\text{A and B}=p(\text{A})\times p(\frac{\text{B}}{\text{A}})

p(\text{A and B})=\frac{5}{36}\times\frac{2}{5}

p(\text{A and B})=\frac{1}{18}

if sum of cards is 8 then probability that one of the cards is 8 is \frac{1}{18}, option C is correct.

3 0
3 years ago
Which equations have the same value of x as Three-fifths (30 x minus 15) = 72? Select three options.
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The question is at what price x will the company maximize revenue.

The revenue function is:

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The company will maximize its revenue when the price is $204.

7 0
3 years ago
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