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valentina_108 [34]

3 years ago

10

Cole's age is 3 years less than his sister Tina's age, t. If Cole is 18, which equation represents this situation, and how old i

s Tina?

2 answers:

Ket [755]3 years ago

4 0

Answer:

the age between Cole's and Tina's is 15 times

steposvetlana [31]3 years ago

3 0

Answer:

18

Step-by-step explanation:

it less not by a year gxfgfg. bnhb vgbv v. vv vv vbv vvbvbvbv. vv v v

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GUYS I NEED HELP <br> PLEASEEEEEE IM STUCK ON THIS

Lelechka [254]

The answer to the first question is complementary angles.

The measure of angle WOV is 60

the answer to the third question is vertical angles.

The measure of YOZ is 60 because vertical angles are equal to each other and YOZ is vertical to WOV

5 0

3 years ago

2. Tyler has 4 times as much money as Ryan. Find the ratio of Ryan's money to<br> Tyler's money.

Phantasy [73]

Answer:

1:4

Step-by-step explanation:

4 0

3 years ago

A rectangular room is three times as long as it is wide, and its perimeter is 40 meters. Find the width of the room.

spayn [35]

40*3 =120 is the width

3 0

4 years ago

Help really quick pleaseee and thankss :)

ohaa [14]

Answer:

They are adjacent.

Step-by-step explanation:

2x + 4x = 90°

6x = 90°

therefore x = 90°/6 = 15°

4 0

4 years ago

The point P(8, −3) lies on the curve y = 3/(7 − x). (a) If Q is the point (x, 3/(7 − x)), use your calculator to find the slope

yan [13]

Answer:

Slope of the line $PQ is -63.434948.$

Step-by-step explanation:

Given that,

The point $P(8,-3)$ lies on the curve $y=\frac{3}{7-x}$ .

If $Q$ is the point lies on $(x,\frac{3}{7-x} )$ .

To find:- Find the slope of line $PQ$ .

So,

The coordinates of point $Q$ when it lies on $(x,\frac{3}{7-x} )$

if $x=1$ then $y= \frac{3}{7-1} =\frac{3}{6} =\frac{1}{2}$

So, $Q$ ≡ $(1,\frac{1}{2} )$ and many points can be calculated by given Equation.

Using the formula when two points $(x_{1} ,y_{1} ) \& (x_{2}, y_{2} )$ .

$Slope=Tan\theta = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Then, substituting the coordinates we get,

$Slope = \frac{1-8}{\frac{1}{2}-(-3) }$

$Slope = \frac{-7}{\frac{1}{2}+3 } = \frac{-7}{\frac{7}{2} }$

$Slope = \frac{-14}{7}=-2$

$tan\theta=-2$ ⇒ $\theta = tan^{-1} (-2)$

$\theta= -63.434948$

Therefore,

Slope of the line $mPQ is -63.434948.$

7 0

3 years ago