Y + 4x < 8
y < -4x + 8
2 points that satisfy this are (0,8) and (2,0)....and those happen to be ur x and y intercepts (where the line crosses the x and y axis)
graph...so go ahead and plot ur x and y intercepts (0,8) and (2,0).....ur slope is - 4.....so start at ur y int (0,8) and go down 4 spaces, and to the right 1...plot that point, then go down 4 spaces and to the right 1, then plot that point...keep doing this and u will have ur line...u should have crossed the x axis at (0,2)......ur line will be a dashed line since the problem has no equal sign.... the shading will go below the line because it is less then.
y - 3 > = 1/2x
y > = 1/2x + 3
2 points that satisfy this are : (0,3) and (-6,0)...ur x and y intercepts
graph : plot ur intercepts (0,3) and (-6,0)....u have a slope of 1/2...so start at ur x intercept (-6,0) and go up 1 space, and to the right 2 spaces, plot that point...then go up 1 and to the right 2, plot that point...keep doing this and u will cross the y axis at (0,3)....this line will be a solid line....the shading will go above the line.
-4 is the slop of the line
Answer: y= 1/3 x + 5/3
Step-by-step explanation:
1= 1/3(-2) + b where b is the y intercept
1= -2/3 + B
+2/3 +2/3
B = 5/3
so we know the slope and the y- intercept
y= 1/3x + 5/3 check: 1=1/3(-2) +5/3
1 =1
Answer:
∠A = 84°
Step-by-step explanation:
Since AB and AC are tangent to the circle, ∠ABK = 90° and ∠ACK = 90°.
Angles of a quadrilateral add up to 360°, so:
∠A + 90° + 90° + 96° = 360°
∠A = 84°
19 because 6 divided by 3 = 2 + 17 ?
