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tatuchka [14]
4 years ago
5

HELP! Parellel lines and transversal

Mathematics
1 answer:
amm18124 years ago
4 0
m\angle 7=180-m\angle1=180-140=40
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2(4+c)=67 help solve for c
vesna_86 [32]

Answer:

c = 29.5 or

c = 59/2

Step-by-step explanation:

2 (4 + c) = 67

8 + 2c = 67

8 - 8 + 2c = 67 - 8

2c = 59

c = 29.5

8 0
3 years ago
you want to put 520 quarters in coin wrappers. you need one wrapper for every $10 in quarters. write an equation you can use to
Lisa [10]
40c=520
This is the proper equation because there are 40 quarters in $10. Thus, if we could only fit $10 worth of quarters in each wrapper, we can only fit 40quarters in each wrapper. C represents the amount of wrappers we will need.

Hope this helps!
6 0
4 years ago
14. Find mMK please :)
MrRissso [65]

Answer:

Step-by-step explanation:

11) strategy:  since they tell us. indirectly,  that the length of  JK is the same as LM then we can set those two equal, solve for X  and then.. when we have X we can figure out the lenght of JK  and LM and then just divide that by 2 go get PK  ( :0 Player Killer ???  no , not that PK)    

solve JK and LM

3x + 23 =9x-19

42 = 6x

7 = x

now that we know x = 7 plug it into either equation to come up with the length of JK or LM .  I'll pick JK just b/c it was 1st

3(7) + 23 = JK

21+23 = JK

44 = JK

now take half of 1/2*JK= 22  that is PK    ( are you sure that 's not player killer?)

PK = 22

12) strategy: set the two arcs BG and GC equal and solve for X, then plug x into either equation and the multiply the answer by 2 to find arc AB

9x-20 = 5x + 28

4x = 48

X = 12

9(12) -20 = BG

88 = BG

2*88 + AB

176 = AB

13) done

14)  strategy: find the angle at L,  and that will also be the arc of MK

<em>copy and past the below</em> helpful trig functions into your computer

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

<em>copy and past the above</em> :

use which ever trig function you want , we have all the sides of the triangle, I'll use CAH

Cos(Ф) = 9/15

Ф = arcCos(9/15)

Ф = 53.13010°

arc MK = 53.13010°

15)   strategy:  arc JK is just 2 times MK

2*MK = 106.26020°

arc MK = 106.26020°

16) find arc JPK   strategy:  JPK is just the remaining part of a full circle of 360 - MK  = 253.7397°

arc JPK = 253.7397°

7 0
3 years ago
The dimensions of a triangle with base 10 in. and height 4.8 in. are multiplied by 4. How is the area affected?​
Shalnov [3]

Answer:

It gets 4 times larger.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the measure of? angle PQR<br> [Not drawn to scale)<br> -51<br> -55<br> -74<br> -78
soldi70 [24.7K]

<u>Given</u>:

The exterior angle P is 74°

The measure of ∠PRQ is 51°

We need to determine the measure of ∠PQR

<u>Measure of ∠QPR:</u>

From the figure, it is obvious that P is the intersection of the two lines.

The angle 74° and ∠QPR are vertically opposite angles.

Since, vertically opposite angles are always equal, then the measure of ∠QPR is 74°

Thus, the measure of ∠QPR is 74°

<u>Measure of ∠PQR:</u>

The measure of ∠PQR can be determined using the triangle sum property.

Thus, we have;

\angle PQR+\angle QPR+\angle PRQ=180^{\circ}

Substituting the values, we get;

\angle PQR+74^{\circ}+51^{\circ}=180^{\circ}

       \angle PQR+125^{\circ}=180^{\circ}

                  \angle PQR=55^{\circ}

Thus, the measure of ∠PQR is 55°

Hence, Option B is the correct answer.

4 0
3 years ago
Read 2 more answers
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