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almond37 [142]
3 years ago
7

Classify each triangle with the given side lengths as Acute, Obtuse, or Right

Mathematics
2 answers:
Dahasolnce [82]3 years ago
4 0

Answer:

acute

Step-by-step explanation:

levacccp [35]3 years ago
4 0

Answer:

<u>Right Triangle</u>

Step-by-step explanation:

12, 16 > 20

20^{2} = 12^{2} +  16^{2}

400 = 144+256

400 = 400

<u>Right Triangle </u>

<u />

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A same side interior angle of two parallel lines is five times smaller than the other same side interior angle. Find the measure
mafiozo [28]

Answer:

30°  and 150°

Step-by-step explanation:

Let the smaller side is x then other side is 5x,

x+5x=180°[interior property]

on solving we get

6x=180°

x=30°

therefore the other side is 5x=5*30°=150°

8 0
3 years ago
Triangle ABC is similar to triangle XYZ. Set up a proportion to solve for x
Hitman42 [59]
Answer:15

10/25 = 6/x

cross multiply:
25 x 6 = 150
10 x (x) = 10x

divide 10x from 150

150/10x = 15
3 0
3 years ago
What is the area of this polygon?
Tatiana [17]

316 cm²

A polygon is given to us and we are interested in finding out the area of the polygon .

  • Here we can see that the polygon is made up of a rectangle and a triangle .

We can separately find out their areas and then add them up to find out the area of the polygon.

So that ,

\sf\longrightarrow Area = ar(\triangle)+ ar(\blacksquare)  \\

  • We know that the area of rectangle is length × breadth and that of triangle is 1/2 × base × height . So ,

\sf\longrightarrow Area = \dfrac{1}{2}(base)(height) + (length)(breadth) \\

  • Here height of triangle can be calculated by subtracting the lengths 18cm and 14cm and its base can be calculated by subtracting CD from BD ( see figure in attachment.)

\sf\longrightarrow Area = \dfrac{1}{2}(4cm)(11cm)+(21cm)(14cm)\\

\sf\longrightarrow Area = 22cm^2 + 294cm^2\\

\sf\longrightarrow \underline{\boxed{\bf Area_{(polygon)}= 316cm^2}} \\

4 0
3 years ago
Read 2 more answers
Its due tomorrow plz help
Alona [7]
If you graph these points you can easily see that the slope is 1 and the y-intercept is -3. Therefore y=x-3.
8 0
3 years ago
8 A test rocket is fired and follows a path described by y = 0.1x(200 – x). The height is y metres above
balandron [24]

Answer:

a) The rocket travels 200 meters horizontally.

b) The height of the rocket mid-flight is of 1000 meters.

Step-by-step explanation:

Height of the rocket:

The height of the rocket, in meters, after an horizontal distance of x, is given by:

y = 0.1x(200 - x)

a) How far does the rocket travel horizontally?

This is x when y = 0. So

0.1x(200 - x) = 0

Then

0.1x = 0

x = 0

And

200 - x = 0

x = 200

So

The rocket travels 200 meters horizontally.

b How high does the rocket reach mid-flight?

This it the height y when x = 0, so:

y = 20*100 - 0.1*100^2 = 1000

The height of the rocket mid-flight is of 1000 meters.

3 0
3 years ago
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