Answer:
<h2>
8 units²</h2>
Step-by-step explanation:
Let side of the square = a
The , Area of square = a²
Now, Midpoint of Diagonal DB is E
And DE = 2 units
So, DB = 2 DE = 2 × 2 = 4 units
Now, using Pythagoras theorem in ∆ BCD
DB² = DC² + BC²
plug the values
Collect like terms
Evaluate the power
Swipe the side of the equation
Divide both sides of the equation by 2
Calculate
Therefore, The area of the square is 8 sq.units.
Hope this helps..
Best regards!!
Answer:
6 cm
Step-by-step explanation:
If the original side length is x, then the modified square has an area of ...
A = LW
32 = (x +2)(x -2) = x^2 -4
36 = x^2 . . . . . . . . add 4
6 = x . . . . . . . . . . take the square root
The original figure has a side length of 6 cm.
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<em>Check</em>
The modified figure is 8 cm by 4 cm = 32 cm^2.
Answer:
if the measure of an angle is 90°, then the angle is a right angle.
Step-by-step explanation:
p=the measure of an angle is 90°
q=the angle is a right angle
p is the hypothesis of the conditional statement
q is the conclusion of the conditional statement
Answer:
2.63274768567
Step-by-step explanation:
First, note that 3.1415... is p, so 2(3.1415...) is 2pi and 4(3.1415...) is 4pi.
2pi and 4pi are full rotations, which will lead to the same cosine (i.e. cos(x) = cos (x+2pi) = cos(x+4pi) = ... = cos (x+2k*pi)).
So, the expression equals cos0.5 + cos 0.5 + cos0.5 = 3cos0.5 = 3(0.87758256189) = 2.63274768567
I hope this helps! :)
