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vivado [14]
3 years ago
6

Eric starts with 10 milligrams of a radioactive substance. The amount of the substance decreases by 12 each week for a number of

weeks, w. He writes the expression 10(12)w to find the amount of radioactive substance remaining after w weeks. Andrea starts with 1 milligram of a radioactive substance. The amount of the substance decreases by 20% each week for a number of weeks, w. She writes the expression (1−0.2)w to find the amount of radioactive substance remaining after w weeks. Use the drop-down menus to explain what each part of Eric’s and Andrea’s expressions mean.
Mathematics
2 answers:
Nady [450]3 years ago
7 0

Answer:

In Pic

Brainliest?

Step-by-step explanation:

Vesna [10]3 years ago
6 0

Answer: Mark as brainliest "If" help

Step-by-step explanation: Hope It helps,,

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a group of students arrange a picnic each student contributed rupees 61 1 upon 2 the total contribution was rupees 676 1 upon 2
IrinaVladis [17]

Answer:

Now, each student contributes= Rs 61 1/2= Rs 123/2 ( mixed fraction ).

Therefore, total no. of students=Rs (1953/2÷123/2) = 15.87

Rounding off 15.87 to 16.

There were 16 students

(i hope it is correct answer. pls mark as brainliest)

8 0
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Given the line below.
Elza [17]

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The point you were told to use is (-2,2), so point-slope form starts as:

   ( y - 2 ) = -1 • ( x - (-2) )

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Find the measure of arc IK if theta equals 58°
timurjin [86]

Check the picture below.

8 0
2 years ago
When factored completely, the expression p4 - 81 is equivalent to ....
S_A_V [24]
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6 0
3 years ago
Please help, I will mark brainliest.
Bess [88]

Answer:

Step-by-step explanation:

Total number of students who roller skated = 80

Number of students who roller skated with laser tag = 39

Number of students who roller skated with no laser tag = 80 - 39 = 41

Therefore, percentage of students who roller skated with no laser tag = \frac{41}{154}\times 100 = 27%

Since, number of students who played laser tag = 85

Percentage of students who played laser tag = \frac{85}{154}\times 100 = 55%

Total number of students who played no laser tag = 45% of 154 = 69

Number of students with no roller skates and no laser tag = 69 - 41 = 28

Percentage of students with no roller skates and no laser tag = \frac{28}{154}\times 100        

                                                                                                       = 18%

Percentage of students who played with no rollers skates = (30 + 18)%

                                                                                                 = 48%

                                  Laser tag                 No laser tag                Total

Roller skate                     25%                           27%                      52%

No Roller skate               30%                           18%                      48%

Total                                55%                           45%                      100%

7 0
3 years ago
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