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Tom [10]
3 years ago
10

Is this correct? Please help me due today.

Mathematics
1 answer:
gulaghasi [49]3 years ago
5 0
The answer you just put is correct
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The ratio of dogs to cats is 3 to 8. if there are 294 dogs, how many cats are there?
taurus [48]

Answer:

784 cats      Yikes !

Step-by-step explanation:

d/c = 3/8  

              3/8 = 294/c

                        c = 294 * 8/3 = 784 cats

8 0
2 years ago
0.92 is 10 times as much as
jeyben [28]
Well just divide and .92 divided by 10 = .092 because you move the value place. so the tenths go to the hundredths and get .092. .092 is the answer
5 0
3 years ago
At the local grocery store, a 16-ounce bottle of apple juice costs $3.20. What is the cost of the apple juice per ounce? Show wo
oee [108]

<u>The answer is $0.20</u>

<u>When you say 3.20 ÷ 16, it gives you 0.2, but you need to add a zero at the end to make it understandable, so that is how you end up with $0.20</u>



4 0
4 years ago
6k ÷ 7 = -3<br> Solve for k
fomenos

Answer:

k = -3.5

Step-by-step explanation:

6k ÷ 7 = -3

Multiply 7 to both sides

6k = -21

Divide both sides by 6

6k/6 = -21/6

k = -3.5

To check if the answer is correct or not, you can always plug in -3.5 for k in the equation.

6(-3.5) ÷ 7 = -3

-21 ÷ 7 = -3

-3 = -3

-3 equals -3 so it is correct that k = -3.5

4 0
3 years ago
Two possible solutions of √11-2x=√x^2+4x+4 are –7 and 1. Which statement is true? A) Only x = –7 is an extraneous solution.
11111nata11111 [884]

Answer:

Option D)Neither solution is extraneous.

Step-by-step explanation:

we have

\sqrt{11-2x}=\sqrt{x^{2}+4x+4}

we know that

two possible solutions are x=-7 and x=1

<u><em>Verify each solution</em></u>

Substitute each value of x in the expression above and interpret the results

1) For x=-7

\sqrt{11-2(-7)}=\sqrt{-7^{2}+4(-7)+4}

\sqrt{25}=\sqrt{25}

5=5 ----> is true

therefore

x=-7 is not a an extraneous solution

2) For x=1

\sqrt{11-2(1)}=\sqrt{1^{2}+4(1)+4}

\sqrt{9}=\sqrt{9}

3=3 ----> is true

therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

7 0
3 years ago
Read 2 more answers
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