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OLEGan [10]
3 years ago
13

Can I have the answer to this question please

Mathematics
1 answer:
Crazy boy [7]3 years ago
6 0

answer = 9c²d^8

(3cd^4)^2

=(3)^2 × c^2 × (d^4)^2

=9×c^2×d^8 ----law of indices (a^m)^n = a^mn

=9c²d^8

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Anika [276]

Answer:48

Step-by-step explanation:

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Slope: 2<br> Point: (3,-5)
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Where is the question? It’s 2(3)
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(x,-2) and (-9,1);slope: -3
amid [387]

Answer:

x= -10

Step-by-step explanation:

The equation is y2-y1 over x2 over x1 so

1-(-2) over -9-(x)=3

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3/-9-x   times -9-x  = 3  times -9-x

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3 years ago
What is meant by the term 'domain'?
damaskus [11]
B the set of input values for the function.
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3 years ago
If 47400 dollars is invested at an interest rate of 7 percent per year, find the value of the investment at the end of 5 years f
Anni [7]

Answer:

Part A) Annual \$66,480.95  

Part B) Semiannual \$66,862.38  

Part C) Monthly \$67,195.44  

Part D) Daily \$67,261.54  

Step-by-step explanation:

we know that

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

so

Part A) Annual

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=1  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{1})^{1*5}  

A=\$47,400(1.07)^{5}  

A=\$66,480.95  

Part B) Semiannual

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=2  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{2})^{2*5}  

A=\$47,400(1.035)^{10}  

A=\$66,862.38  

Part C) Monthly

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=12  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{12})^{12*5}  

A=\$47,400(1.0058)^{60}  

A=\$67,195.44  

Part D) Daily

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=365  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{365})^{365*5}  

A=\$47,400(1.0002)^{1,825}  

A=\$67,261.54  

8 0
3 years ago
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