Answer:
Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)
Problem 2) Runner B has the smallest period
Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.
Step-by-step explanation:
The frequency of the football player is 160 heartbeats per minute.
The period is (using the equation you showed above):
second problem:
Runner A does 200 loops in 60 minutes so his frequency is:
loops per minute
then the period is: 0.3 minutes (does one loop in 0.3 minutes)
the other runner does 200 loops in 65 minutes, so his frequency is:
loops per minute
then the period is:
Therefore runner B has the smaller period
Answer:
10.8333......
Step-by-step explanation:
First 65 divided by 6 is equal to 10.8333......
So the answer was 10.8333......
Just multiply them together and get a4-2a2-24.
(a2-6)(a2+4)
F: a4
O:4a2
I:-6a2
L:-24
Add together
a4-2a2-24
Answer:
70
Step-by-step explanation:
The answer is <em>B. 6 ÷ D</em>