You don't need to regroup when adding a two-digit number with a number.
Answer:
0
Step-by-step explanation:
If ∑aₙ converges, then lim(n→∞)aₙ = 0.
Using ratio test, we can determine if the series converges:
If lim(n→∞) |aₙ₊₁ / aₙ| < 1, then ∑aₙ converges.
If lim(n→∞) |aₙ₊₁ / aₙ| > 1, then ∑aₙ diverges.
lim(n→∞) |(100ⁿ⁺¹ / (n+1)!) / (100ⁿ / n!)|
lim(n→∞) |(100ⁿ⁺¹ / (n+1)!) × (n! / 100ⁿ)|
lim(n→∞) |(100 / (n+1)|
0 < 1
The series converges. Therefore, lim(n→∞)aₙ = 0.
Answer:
is a polynomial
Step-by-step explanation:
a polynomial is a set of numbers with multiple terms that are not simplify able
is not a polynomial because its actually one term, there is no addition/subtraction of different terms.
-13 is a single number, so not a polynomial
13x^-2 is also a single number, not a polynomial
Answer:
Step-by-step explanation:
m + j + s = 37
j = 2s......s = j/2 or 1/2j
m = j + 2
(j + 2) + j + (1/2j) = 37
2j + 1/2j = 37 - 2
2j + 1/2j = 35....multiply everything by 2 to get rid of the fraction
4j + j = 70
5j = 70
j = 70/5
j = 14 < ==== Jan is 14
m = j + 2
m = 14 + 2
m = 16 <==== marcia is 16
s = 1/2j
s = 1/2(14)
s = 14/2
s = 7 <==== sydney is 7
Answer:
Using Pyhagoras theoram,
(H)^2 = (B)^2 + (P)^2
B = 13 in
P = 5 in
![(h)^{2} = (13)^{2} + {(5)}^{2} \\ = > (h)^{2} = 169 + 25 \\ = > (h)^{2} = 194 \\ = > h = \sqrt{194} \\ = > h = 13.92](https://tex.z-dn.net/?f=%28h%29%5E%7B2%7D%20%20%3D%20%2813%29%5E%7B2%7D%20%20%2B%20%20%7B%285%29%7D%5E%7B2%7D%20%20%5C%5C%20%3D%20%20%3E%20%20%28h%29%5E%7B2%7D%20%20%3D%20%20169%20%2B%2025%20%5C%5C%20%20%3D%20%20%3E%20%28h%29%5E%7B2%7D%20%20%3D%20194%20%5C%5C%20%20%3D%20%20%3E%20h%20%3D%20%20%5Csqrt%7B194%7D%20%20%5C%5C%20%20%3D%20%20%3E%20h%20%3D%2013.92)
Hence, the missing side is 13.92 inhes.