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2 years ago

7

A treasure hunter discovered a buried treasure chest filled with a total of 656 gems. 44 of the gems were diamonds, and the rest

were rubies. How many of the gems were rubies?

1 answer:

UNO [17]2 years ago

5 0

Answer:612

Step-by-step explanation: take 656 and subtract 44 diamonds to get the remaining rubies 656-44= 612

You might be interested in

What is the range for this set of data? 7, 15, 12Mrs. Juarez graded ten English papers and recorded the scores. 92, 95, 100, 62,

ra1l [238]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Please find the complete question in the attached file.

Arrange the value into the ascending order:

$62, 88, 89, 90, 92, 95, 96, 98, 100, 100$

Calculating the Range:

$= Greatest - Lowest\\\\= 100 - 62\\\\ = 38$

Outlier = This might be the value "far" from other data values= 62

The range of scores would be, sans outlier,

$88, 89, 90, 92, 95, 96, 98, 100, 100$

Calculating the range without outlier $= 100 - 88 = 12$

Inter Quartile Range $= Q_3 - Q_1$

$IQR = 98 - 89 = 11$

Calculating the IQR without outlier $= 99 - 89.5 = 9.5$

Therefore,

Option a is "True".

Option b is "True".

Option c is "True".

Option d is "False".

Option e is "False".

Option f is "True".

5 0

2 years ago

A 6-pound bag of chocolate candies costs $14.04. What is the unit price?

Ber [7]

Answer:

2.34 per pound is unit price

Step-by-step explanation:

14.04 divided by 6 is 2.34

3 0

3 years ago

A random sample of 85 group leaders, supervisors, and similar personnel revealed that a person spent an average 6.5 years on the

strojnjashka [21]

Answer:

<em>95% of confidence interval for the Population</em>

<em>( 6.1386 , 6.8614)</em>

Step-by-step explanation:

<u><em>Step( i ):-</em></u>

<em>Given random sample size 'n' =85</em>

<em>Mean of the sample size x⁻ = 6.5 years</em>

<em>Standard deviation of Population = 1.7 years</em>

<em>Level of significance = 0.95 or 0.05</em>

<u><em>Step(ii):-</em></u>

<em>95% of confidence interval for the Population is determined by</em>

<em></em> $(x^{-} - Z_{0.05} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.05} \frac{S.D}{\sqrt{n} })$ <em></em>

<em></em> $(6.5 - 1.96\frac{1.7}{\sqrt{85} } , 6.5 + 1.96 \frac{1.7}{\sqrt{85} })$ <em></em>

<em>( 6.5 - 0.3614 , 6.5 + 0.3614 )</em>

<em>( 6.1386 , 6.8614)</em>

<u><em>Conclusion</em></u><em>:-</em>

<em>95% of confidence interval for the Population</em>

<em>( 6.1386 , 6.8614)</em>

8 0

3 years ago

Need more help again

Fittoniya [83]

Answer:

QSR = 68º

Step-by-step explanation:

TSQ + QSR = TSR

15x + (10x - 2) = 173

Combine like terms

25x = 175

Divide both sides by 25

x = 7

QSR = 10x - 2

QSR = 10(7) - 2

QSR = 68º

5 0

3 years ago

PLEASE HELP!!! <br> find the length of arc LN. Round to the nearest hundredth.<br> SHOW WORK....

patriot [66]

9514 1404 393

Answer:

15.71 units

Step-by-step explanation:

The arc length is given by the formula ...

s = rθ

where r represents the radius, and θ represents the central angle in radians.

The angle of 60° is π/3 radians, so the arc length is ...

s = 15(π/3) = 5π ≈ 15.71 . . . units

LN ≈ 15.71 units

__

<em>Note</em>: if you use 3.14 for π, you will get 15.70.

6 0

2 years ago