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scZoUnD [109]
3 years ago
5

Marylou is blowing up a beach ball. The package says that the ball has a diameter of 12 inches. What is the volume of the beach

ball when it is completely full? Use 3.14 for PI . A. 452.16 cubic inches B. 904.32 cubic inches C. 301.44 cubic inches D. 7,234.56 cubic inches
Mathematics
1 answer:
elena55 [62]3 years ago
4 0
V = 4/3 x 3.14 x 6³
V = 904.32

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The sum of two consecutive integers is -239 find the two integers​
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Answer:

The two consecutive integers are -119 and -120

Step-by-step explanation:

As we know that these two integers are consecutive, that means that they will have a difference of 1. This means that we can find the two integers by adding 1 to the sum of -239 and then dividing it by two

1-239=-238\\\frac{-238}{2} =-119\\-119-1=-120

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4 years ago
Find the area of an equilateral triangle (regular 3-gon) with the given measurement.
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Phred has already graded 40 papers and he still needs to grade more. Write an equation for how many papers he is grading if he c
vladimir2022 [97]

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3 years ago
At a local University, it is reported that 81% of students own a wireless device. If 5 students are selected at random, what is
Sphinxa [80]

Answer:

34.87% probability that all 5 have a wireless device

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

81% of students own a wireless device.

This means that p = 0.81

If 5 students are selected at random, what is the probability that all 5 have a wireless device?

This is P(X = 5) when n = 5. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.81)^{5}.(0.19)^{0} = 0.3487

34.87% probability that all 5 have a wireless device

5 0
3 years ago
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