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Dvinal [7]
3 years ago
12

Which statement can be represented by the equation 18 divided by m = 7.2?

Mathematics
2 answers:
mart [117]3 years ago
8 0

Answer:

A number,m,is seven point two . Eighteen divided by a number,m,is seven point two

kolezko [41]3 years ago
6 0

Answer:

its c

Step-by-step explanation:

just to make it easier for you:)

You might be interested in
7n + 5 =68.... how to solve this problem and show my work​
mart [117]

Answer:

n=9

Step-by-step explanation:

7n+5=68  Subtract 5 on both sides.

    <u>-5  -5</u>

7n=63       Divide both sides by 7.

<u>/7   /7</u>

n=9

Hope this helps! Have a nice day ^^

7 0
3 years ago
Read 2 more answers
Least to greatest -6.8,|-23/4|,0,-14.4,|-1.9|,5.4
IrinaVladis [17]

Answer:

From Least to Greatest: -14.4, -6.8, -23/4, -1.9, 0, 5.4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the sum of natural numbers less than 200 neither divisible by 3 nor by 5
Sveta_85 [38]

Step-by-step explanation:

The required sum 

=(1+2+3+...+199)−(3+6+9+...+198)−(5+10+15+...+195)+(15+30+45+...+195)

=2199(1+199)−266(3+198)−239(5+195)+213(15+195)

 

=199×100−33×201−39×100+13×105=10732

8 0
2 years ago
Read 2 more answers
The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct
lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

y=\dfrac{x}{1+x}

Point P\left(1,\dfrac{1}{2}\right) lies on the curve.

Point Q\left(x,\dfrac{x}{1+x}\right) is an arbitrary point on the curve.

The slope of the secant line PQ is

\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]

1. If x=0.5, then the slope is

\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333

2. If x=0.9, then the slope is

\dfrac{1}{2(0.9+1)}=\dfrac{1}{3.8}\approx 0.2632

3. If x=0.99, then the slope is

\dfrac{1}{2(0.99+1)}=\dfrac{1}{3.98}\approx 0.2513

4. If x=0.999, then the slope is

\dfrac{1}{2(0.999+1)}=\dfrac{1}{3.998}\approx 0.2501

5. If x=1.5, then the slope is

\dfrac{1}{2(1.5+1)}=\dfrac{1}{5}\approx 0.2

6. If x=1.1, then the slope is

\dfrac{1}{2(1.1+1)}=\dfrac{1}{4.2}\approx 0.2381

7. If x=1.01, then the slope is

\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488

8. If x=1.001, then the slope is

\dfrac{1}{2(1.001+1)}=\dfrac{1}{4.002}\approx 0.2499

7 0
3 years ago
Use rounding to estimate 0.93+0.18 plz help me
Anastasy [175]
0.93 = 0.9
0.18 = 0.2 

0.9 + 0.2 = 1.1

Answer 1.1
6 0
3 years ago
Read 2 more answers
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