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inna [77]
2 years ago
5

The diameter of Circle terminates on the circumference of the circle at​ (3,0) and (3,−7).. Write the equation of the circle in

standard form. Show all of your work for full credit.
Mathematics
1 answer:
Verdich [7]2 years ago
7 0

Step-by-step explanation:

that means the center of the circle is exactly in the middle between the 2 points.

and since both points have the same x value (so, the diameter here is a vertical line), it is ready to get the y value of the middle : (-7 - 0) / 2 = -3.5

so, the coordinates of the center are (3, -3.5).

and that makes the standard circle equation

(x - h)² + (y - k)² = r²

to

(x - 3)² + (y + 3.5)² = 3.5² = 12.25

as h, k are the coordinates of the center, and r is the radius (half the diameter).

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Step-by-step explanation:

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What is the value of y?
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Y= 5.91 yup that’s the answer
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Identify the slope (m) and y-intercept (b) of each linear equation.<br> 52. 3x+4y=24
nekit [7.7K]

Answer:

Step-by-step explanation:

  [1]    3x - 4y = -24

  [2]    -x - 16y = -52

Graphic Representation of the Equations :

   -4y + 3x = -24        -16y - x = -52  

 

Solve by Substitution :

// Solve equation [2] for the variable  x

 [2]    x = -16y + 52

// Plug this in for variable  x  in equation [1]

  [1]    3•(-16y+52) - 4y = -24

  [1]     - 52y = -180

// Solve equation [1] for the variable  y

  [1]    52y = 180

  [1]    y = 45/13

// By now we know this much :

   x = -16y+52

   y = 45/13

// Use the  y  value to solve for  x

   x = -16(45/13)+52 = -44/13

Solution :

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8 0
3 years ago
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Answer:

Step-by-step explanation:

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Equation of the line will be,

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2). Equation of a line having slope 'm' and passing through a point (x', y') is,

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3). Equation of a line passing through two points (x_1, y_1) and (x_2,y_2) will be,

y-y_1=\frac{(y_2-y_1)}{(x_2-x_1)}(x-x_1)

If this line passes through (-2, 3) and (-3, 4),

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y - 3 = -1(x + 2)

y = -x - 2 + 3

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4 0
3 years ago
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jeyben [28]

Answer:

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because max is -25

3 0
3 years ago
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