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liq [111]
3 years ago
10

Three balls are packaged in a cylindrical container as shown below. The balls just touch the top, bottom, and sides of the cylin

der. The diameter of each ball is 13 cm. What is the total volume of the three balls?
-pls hurry and explain,thanks​

Mathematics
1 answer:
sp2606 [1]3 years ago
3 0

Answer:

3,451 cm³

Step-by-step explanation:

The ball is a sphere.

Formula for finding the volume of a sphere = ⁴/3*πr³

Volume of the 3 balls = 3(⁴/3*πr³)

Where,

radius (r) = ½ of diameter = ½(13) = 6.5 cm

Plug in the values into the formula:

Volume of the 3 balls = 3(⁴/3*π*6.5³)

= 4*π*274.625

= 3,451.03953 ≈ 3,451 cm³

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6 0
3 years ago
Find three consecutive odd integers such that the sum of the first and the third is 34,
nataly862011 [7]

Answer:

15,17,19

Step-by-step explanation:

assume the first number is X which means the third number will be X+4 so X+ X+4=34

solve for X which will be 15

thus the numbers are 15,17 and 19

6 0
3 years ago
Factor 26r3s + 52r5 – 39r2s4.
algol [13]

Answer:

13r²(2rs + 4r³ - 3s⁴)

Step-by-step explanation:

In equation 26r³s + 52r⁵ - 39r²s⁴;

The GCF of 26, 52, and 39 = 13

The GCF of r³, r⁵ and r² = r²

The GCF of s, (no "s"), and s⁴ = no "s" (Since one of the number doesn't have "s")

Now we can factor out 13r² from all three expressions;

26r³s + 52r⁵ - 39r²s⁴

=> <em>13r²(2rs) + 13r²(4r³) - 13r²(3s⁴)</em>

To factor it all together;

<u>13r²(2rs + 4r³ - 3s⁴)</u>

Hope this helps!

7 0
3 years ago
The graph at the right shows the race between Tristin, the tortoise, and Harlow, the hare. A)Express Tristin’s constant speed.
mafiozo [28]

Answer:

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Step-by-step explanation:

(id like to tell you the rest but i can't cause then it would be plagiarism. hope you understand)

5 0
3 years ago
Tan 45°. tan² 30° tan 60° <br>slove it​
makvit [3.9K]

Answer:

\frac{\sqrt{3} }{3} or \frac{1}{\sqrt{3} }

Step-by-step explanation:

We can break the problem into three parts,

tan45 = sin(45)/cos(45)=\frac{\frac{\sqrt{2}}{2} }{\frac{\sqrt{2}}{2} } =1

tan^{2}30 =(tan30))^{2}=(sin30/cos30)^2=((1/2)/(\sqrt{3}/2))^2 =(1/\sqrt{3})^2

tan60=sin60/cos60=\frac{\sqrt{3}/2 }{1/2} =\sqrt{3}

Then, tan45*tan^230*tan60=1*(1/sqrt(3))^2*sqrt(3)=1/sqrt(3)=sqrt(3)/3

Therefore, the solution is sqrt(3)/3

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2 years ago
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