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3 years ago

What’s the answer to this please I give 5 star and brainliest

Mathematics

1 answer:

Gemiola [76]3 years ago

8 0

Answer:

I think its a im not 100% sure though.

Step-by-step explanation:

Can i have brainliest

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The Johnson family is trying to conserve energy by having lights on in the house no more than 105 minutes a day. If they have al

bagirrra123 [75]

Answer:

Step-by-step explanation:

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3 years ago

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The volume of 10

Alona [7]

Hello!

1 floz divided by 100 = 0.01
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4 years ago

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(01.02) kim earns $30 for babysitting on friday nights. she makes an average of $1.25 in tips per hour. write the function of ki

defon

Y = 1.25x + 30 <== ur function

for 3 hrs.....x = 3
y = 1.25(3) + 30
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8 0

3 years ago

Bowl A contains 6 apples and 3 mangoes this can be written as, Bowl B contain 8 apples and 2 mangoes this can be written as. Wha

Andrew [12]

Answer:

Bowl B contains 2 apples more than Bowl A and Bowl A contains 1 mango more than Bowl B.

Step-by-step explanation:

Number of apples in Bowl A = 6

Number of mangoes in Bowl B = 8

Difference in apples = 8 - 6 = 2

So, Bowl B contains 2 apples more than Bowl A.

Number of mangoes in Bowl A = 3

Number of mangoes in Bowl B =2

Difference in mangoes = 3 - 2 = 1

So, Bowl A contains 1 mango more than Bowl B.

3 0

3 years ago

A certain plant runs three shifts per day. Of all the items produced by the plant, 50% of them are produced on the first shift,

Snezhnost [94]

Answer:

0.2941 = 29.41% probability that it was manufactured during the first shift.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: Manufactured during the first shift.

Probability of a defective item:

1% of 50%(first shift)

2% of 30%(second shift)

3% of 20%(third shift).

$P(A) = 0.01*0.5 + 0.02*0.3 + 0.03*0.2 = 0.017$

Probability of a defective item being produced on the first shift:

1% of 50%. So

$P(A \cap B) = 0.01*0.5 = 0.005$

What is the probability that it was manufactured during the first shift?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.005}{0.017} = 0.2941$

0.2941 = 29.41% probability that it was manufactured during the first shift.

6 0

3 years ago