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Alex17521 [72]
3 years ago
7

AJKL is similar to ARST. What is the value of x?

Mathematics
2 answers:
dlinn [17]3 years ago
4 0

Answer:

15

Step-by-step explanation:

(12/8) ×10 is the correct answer

tia_tia [17]3 years ago
4 0
15 is your answer ..........
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What is the slope of a line perpendicular to 3x- 2y= 6
Tema [17]

Answer:

y = (-2/3)x + 5

2y=3x-6 Then divide by 2. y=3/2x-6 Now it is in slope-intercept form. The slope for this particular equation is 3/2 (m). The slope of a line that is perpendicular to this would be -2/3, the negative reciprocal of 3/2.

Step-by-Step:

HOPE THIS HELPED!!!

5 0
3 years ago
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If Rita receives $45.34 interest for a deposit earning 4% simple interest for 160 days, what is the amount of her deposit? (Roun
vovangra [49]

Answer:

6.4

Step-by-step explanation:

5 0
3 years ago
Simplify √ 105 ..................................
olya-2409 [2.1K]

Answer:

Simplify √ 105  

A. 2√ 7  

B. 2√ 3  

<u>C. √ 105 </u>

D. √ 42

Step-by-step explanation:

8 0
3 years ago
Describe and correct the error in writing an equation of the line shown
Rudiy27

Answer:

y  = -\frac{3}{5}x+4

Step-by-step explanation:

Given:

(x_1,y_1) = (0,4)

(x_2,y_2) = (5,1)

The attachment completes the question

From the attachment, the slope of the line was calculated as:

m = \frac{1-4}{0-5}

This step is inaccurate because the slope of a line is calculated using

m = \frac{y_2-y_1}{x_2-x_1}

Which gives

m = \frac{1-4}{5-0}

m = \frac{-3}{5}

m = -\frac{3}{5}

The line equation is then calculated using:

y -y_1 = m(x - x_1)

Substitute values for m, x1 and y1

y - 4 = -\frac{3}{5}(x - 0)

y - 4 = -\frac{3}{5}(x)

Open bracket

y - 4 = -\frac{3}{5}x

Make y the subject

y  = -\frac{3}{5}x+4

6 0
3 years ago
Anyone know the answers 11 through 20?
Evgen [1.6K]

Step-by-step explanation:

11) x^5

12) 5x^2

13) x+21

14) 2x-8

15) 3^3

=3*3*3

=27

16)2^5

=2*2*2*2*2

=32

17) 5^4

=5*5*5*5

=625

18)2 times a number p squared

19)3 times a number m fifth power

20)the addition of half a number and 2

5 0
3 years ago
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