Instructions: Find the missing length

Please help me with this question!

Nata [24]

Answer:

true, it will always divide the opposite side in halff

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Help urgently please❤️ I’ll mark u brainlyest thank u

ELEN [110]

Answer:

-1/2 and 2

Step-by-step explanation:

Since you need y=mx+b you have to convert your equation to match this

So, 3x+6y=12

Subtract 3x from both sides to get the y term on the left side alone.

This leaves 6y=-3x+12

From there divide 6 from both sides to give you your y term alone on the left side completely.

That leaves you with y=-1/2x+2

Meaning your M=-1/2 and your B=2

Your graph then should have the start point be at y=2 from there move -1 spaces down the y axis, and go to spaces to the right. Making your line move between r and n

6 0

3 years ago

A tape diagram. There are 65 students out of 100 students who ride the bus. There are question mark students out of 800 students

SVEN [57.7K]

Answer:

800÷100 = 8

65×8=520

$\frac{520}{800}$

another way:

100%-65%=35%

35% = 0.35

800×0.35= 280

800-280=520

another way:

65% = 0.65

0.65×800=520

Hope it helped! :)

6 0

2 years ago

“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor

Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

$C=2\pi r$

Find the radius of the sphere with a 5.50-meter circumference

For $C=5.50\ m$

assume

$\pi =3.14$

substitute and solve for r

$5.50=2(3.14)r$

$r=5.50/[2(3.14)]=0.88\ m$

Find the radius of the sphere with a 7.85-meter circumference

For $C=7.85\ m$

assume

$\pi =3.14$

substitute and solve for r

$7.85=2(3.14)r$

$r=7.85/[2(3.14)]=1.25\ m$

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

$SA=4\pi r^{2}$

Find the surface area of sphere with a 5.50-meter circumference

For $r=0.88\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(0.88)^{2}$

$SA=9.73\ m^{2}$

Find the surface area of sphere with a 7.85-meter circumference

For $r=1.25\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(1.25)^{2}$

$SA=19.63\ m^{2}$

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

Find the cost of sphere with a 5.50-meter circumference

$9.73*(92)=\$895.16$

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Find the cost of sphere with a 7.85-meter circumference

$19.63*(92)=\$1,805.96$

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0

3 years ago

katie collets stamp she has stamps from canada, United Staes,ands Rest of the world in a ratio of 1:1.2:1.5 she has 135 stamps f

lyudmila [28]

Answer:

90 stamps from Canada, 108 stamps from the United States, and 135 stamps from the Rest of the World

Step-by-step explanation:

Since this is a problem of proportion we can use the Rule of three to solve this. We do this by multiplying the diagonal available values and dividing by the third value in order to get the missing variable, which in this case would be the number of stamps in the other country. Like so...

1.5 <=====> 135 stamps

1.2 <=====> x stamps (United States)

(1.2 * 135) / 1.5 = 108 stamps (United States)

1.5 <=====> 135 stamps

1 <=====> x stamps (Canada)

(1 * 135) / 1.5 = 90 stamps (Canada)

Finally, we can see that Katie had 90 stamps from Canada, 108 stamps from the United States, and 135 stamps from the Rest of the World. All creating a ratio or 1:1.2:1.5

8 0

3 years ago