Simplify the expression: 1/1+cot^2x
1 answer:
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Step-by-step explanation:
EF is a segment so it's a line with the end points as E and F. Line RS bisects(cuts in half) line EF. Then where the two lines meet is where A is.
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The vertex form of the given quadratic equation is
.
According to the given question.
We have a quadratic equation
Since, for the standard quadratic form is , the vertex form of a quadratic equation is
where (h, k) is the vertex.
And h and k can be calculated as
h = -b/2a and y = k
So, for the given equation the vertex (h, k) is given by
h = -(-8)/2(4) = 8/8 = 1 (X coordinate of vertex)
and,
substitute x = 1 in the above equation for the value of k
Y = 4(1)(1) - 8(1) + 20
⇒ Y = 4 - 8 + 20
⇒ Y = -4 + 20
⇒ Y = 16
so, k = 16 (Y coordinate of vertex)
Now, substitute the value of a, k and h in .
⇒
Therefore, the vertex form of the given quadratic equation is
.
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