Question

A ball is thrown into the air with a speed of 32 feet per second. The function h=32t - 16t^2 models the height of the ball after t seconds. How many seconds does it take for the ball to reach its maximum height?

Answer 1

Answer:

t = 1 s

Step-by-step explanation:

The function models the height of the ball after t seconds is given by :

$h=32t - 16t^2$

We need to find how many seconds does it take for the ball to reach its maximum height.

For maximum height put dh/dt = 0

$\dfrac{dh}{dt}=\dfrac{d}{dt}(32t - 16t^2)\\=32-32t$

So,

32-32t = 0

t = 1

So, it will take 1 second to reach its maximum height.